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18 Jun 2006, 03:46
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N
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Hi
Some Thoughts
Some Thoughts
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18 Jun 2006, 04:29
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A it is
We pretend that when Lisa and Paul meet each other, Lisa has passed A rooms so Paul must have passed 17-A rooms
In each room, Lisa stay L min and Paul stay P min.
So A*L=(17-A)*P
(1)We have P=3/2L so it is obvious that we can figure A out
(2)is insufficient
We pretend that when Lisa and Paul meet each other, Lisa has passed A rooms so Paul must have passed 17-A rooms
In each room, Lisa stay L min and Paul stay P min.
So A*L=(17-A)*P
(1)We have P=3/2L so it is obvious that we can figure A out
(2)is insufficient
18 Jun 2006, 05:07
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quangviet512
I get (E)... By using your equations
I have a smilar equation as your equation : A*L = (18-A)*P + Constant. The constant exists as there are 3 cases:
> Lisa enters the room and Paul is inside
> Paul enters the room and Lisa is inside
> Paul and Lisa enter the room at the same time
(1) Brings another vairable x which could be a integer from 0 to 9, and as u say:
P/L = (30 + x) / (20 + x) = 10/(20+x) + 1 not sufficient
(2) P = L + 10 not sufficient
(1) & (2) brings no more.
