Last visit was: 20 Sep 2026, 04:13 It is currently 20 Sep 2026, 04:13
Home
Messages
Tests
Schools
Events
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
Back to Forum
Create Topic
505-555 (Easy)|   Geometry|      
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 20 Sep 2026
Posts: 113,680
Own Kudos:
842,448
Given Kudos: 111,671
Products:
GMAT Club Tests
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 113,680
Kudos: 842,448
What is the area of the above right triangle, in terms of x? 02 Sep 2018, 21:59
Kudos
Add Kudos
Bookmarks
Bookmark this Post
00:00
Start Timer
Pause Timer
Resume Timer
Show Answer
Hide
Show
History
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

15% (low)

Question Stats:

90% (01:02) correct 10% (00:55) wrong based on 54 sessions

History

Date
Time
Result
Not Attempted Yet

What is the area of the above right triangle, in terms of x?


A. x^2/2

B. \(\frac{x^2\sqrt{3}}{2}\)

C. \(x^2\sqrt{3}\)

D. 2x^2

E. \(2x^2\sqrt{3}\)


Show Spoiler
Attachment:
image005.jpg
image005.jpg [ 1.59 KiB | Viewed 2484 times ]
ShowHide Answer
Official Answer
B
User avatar
sumit411
User avatar
Joined: 07 Oct 2017
Last visit: 28 Jan 2019
Posts: 210
Own Kudos:
234
Given Kudos: 3
Posts: 210
Kudos: 234
What is the area of the above right triangle, in terms of x? 02 Sep 2018, 22:52
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel

What is the area of the above right triangle, in terms of x?


A. x^2/2

B. \(\frac{x^2\sqrt{3}}{2}\)

C. \(x^2\sqrt{3}\)

D. 2x^2

E. \(2x^2\sqrt{3}\)


Show Spoiler
Attachment:
1535954058494.jpg
1535954058494.jpg [ 77.24 KiB | Viewed 2240 times ]
Show more
Answer is B

Thank you = Kudos
User avatar
Abhishek009
User avatar
Board of Directors
Joined: 11 Jun 2011
Last visit: 17 Dec 2025
Posts: 5,877
Own Kudos:
5,544
Given Kudos: 463
Status:QA & VA Forum Moderator
Location: India
GPA: 3.5
WE:Business Development (Commercial Banking)
Posts: 5,877
Kudos: 5,544
What is the area of the above right triangle, in terms of x? 03 Sep 2018, 08:52
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel

What is the area of the above right triangle, in terms of x?


A. x^2/2

B. \(\frac{x^2\sqrt{3}}{2}\)

C. \(x^2\sqrt{3}\)

D. 2x^2

E. \(2x^2\sqrt{3}\)


Show Spoiler
Attachment:
The attachment image005.jpg is no longer available
Show more
This is a right-angled isosceles triangle
Attachment:
Distance.jpg
Distance.jpg [ 3.44 KiB | Viewed 2278 times ]
So, Area of the Triangle must be \(\frac{x^2}{2}\), Answer must be (A)
User avatar
PKN
User avatar
Joined: 01 Oct 2017
Last visit: 11 Oct 2025
Posts: 809
Own Kudos:
1,692
Given Kudos: 41
Status:Learning stage
WE:Supply Chain Management (Energy)
Posts: 809
Kudos: 1,692
What is the area of the above right triangle, in terms of x? 03 Sep 2018, 10:02
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Abhishek009
Bunuel

What is the area of the above right triangle, in terms of x?


A. x^2/2

B. \(\frac{x^2\sqrt{3}}{2}\)

C. \(x^2\sqrt{3}\)

D. 2x^2

E. \(2x^2\sqrt{3}\)


Show Spoiler
Attachment:
image005.jpg
This is a right-angled isosceles triangle
Attachment:
Distance.jpg
So, Area of the Triangle must be \(\frac{x^2}{2}\), Answer must be (A)
Show more

The given triangle is a 60-90-30 triangle.
So, sides are in the ratio: \(\sqrt{3}x(=base):2x(=hypotenuse):x(=height)\)

Area of triangle=\(\frac{1}{2}*base*height=\frac{1}{2}*\sqrt{3}x*x\)=\(\frac{x^2\sqrt{3}}{2}\)

Ans. (B)
User avatar
ScottTargetTestPrep
User avatar
Target Test Prep Representative
Joined: 14 Oct 2015
Last visit: 18 Sep 2026
Posts: 22,744
Own Kudos:
27,000
Given Kudos: 302
Status:Founder & CEO
Affiliations: Target Test Prep
Location: United States (CA)
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 22,744
Kudos: 27,000
What is the area of the above right triangle, in terms of x? 07 Sep 2018, 17:09
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel

What is the area of the above right triangle, in terms of x?


A. x^2/2

B. \(\frac{x^2\sqrt{3}}{2}\)

C. \(x^2\sqrt{3}\)

D. 2x^2

E. \(2x^2\sqrt{3}\)


Show Spoiler
Attachment:
image005.jpg
Show more

We see that we have a 30-60-90 right triangle, so the base, which is opposite the 60 degree angle, is x√3.

Thus, the area of the triangle is x * x√3 * 1/2 = (x^2√3)/2.

Answer: B
User avatar
HasnainAfxal
User avatar
Joined: 06 Sep 2018
Last visit: 12 Mar 2022
Posts: 124
Own Kudos:
65
Given Kudos: 72
Location: Pakistan
Concentration: Finance, Operations
GPA: 2.87
WE:Engineering (Other)
Products:
My Reviews
Posts: 124
Kudos: 65
What is the area of the above right triangle, in terms of x? 08 Sep 2018, 09:30
Kudos
Add Kudos
Bookmarks
Bookmark this Post
This right triangle is a 30, 60, 90 triangle.
So, its side lengths are \(x\), \(\sqrt{3}x\), \(2x\)
Area =\(\frac{1}{2}*Base*Height\)
Area= \(\frac{1}{2}*x*\sqrt{3}x\)
Area= \(x^2\sqrt{3}x/2\)
Moderator:
Bunuel
Math Expert
113680 posts