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njvenkatesh
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GMAT prep Q3 19 Jul 2006, 14:12
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Hi,

Can someone help with this question ?

Thanks in advance.



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haas_mba07
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GMAT prep Q3 19 Jul 2006, 15:32
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Given m - j = 2 (m -k) & m > j , m > k

Solving m - j = 2m -2k

2k = m+j => Adding k on both sides
3k = (m+j+k) => k = Average.

S1: j = 30, 000

Using this we still dont know k. Not sufficient.

S2: k = 40, 000 sufficient.

Answer: B.
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jamesrwrightiii
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GMAT prep Q3 19 Jul 2006, 20:13
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Quote:
Solving m - j = 2m -2k
Show more

I understand how you get to this point...

Quote:

2k = m+j => Adding k on both sides
3k = (m+j+k) => k = Average.
Show more


However, I am lost how m-j=2m-2 turns into this equation.
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jaynayak
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GMAT prep Q3 20 Jul 2006, 00:38
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B

Given

M-J = 2(M-K)
M+J = 2K

Av = M+J+K / 3
AV = 3K/3 = K

So basically we need K's salary

1) Gives J's salary,
Putting in above equations we still have two unknown variables hence Not suff
2) Gives K's salary hence suff.
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Futuristic
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GMAT prep Q3 22 Jul 2006, 19:13
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hmm, tough one if it does not hit home immediately, got it wrong....
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jamesrwrightiii
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GMAT prep Q3 23 Jul 2006, 13:02
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I am still confused
I get to the point where I get

m=2k-j

Then I am stumped
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jaynayak
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GMAT prep Q3 26 Jul 2006, 02:43
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Let the salaries be M, J and K

Average is M+J+K/3
Also
M-J = 2(M-K)
M- J = 2M - 2K
-M-J = -2K
M+J = 2K

Substituting in Average we get
Av = 3K/3 = K

Hence to find the average we need only kate's salary

B provides that information. Hence B



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
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