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Sub 505 (Easy)|   Exponents|      
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Sajjad1994
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(10^(1/2) + 10^(1/2)/2^(1/2))^2 = 29 Aug 2019, 08:08
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

5% (low)

Question Stats:

85% (00:38) correct 15% (00:34) wrong based on 67 sessions

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Date
Time
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\([\frac{\sqrt{10} + \sqrt{10}}{\sqrt{2}}]^2\)

A. 10
B. 20
C. 50
D. 100
E. 200
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B
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(10^(1/2) + 10^(1/2)/2^(1/2))^2 = 29 Aug 2019, 08:10
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Bunuel PLEASE FIX THE FORMULA.

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Bunuel
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(10^(1/2) + 10^(1/2)/2^(1/2))^2 = 29 Aug 2019, 08:16
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SajjadAhmad
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Bunuel PLEASE FIX THE FORMULA.

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Fixed the formula.
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nipun12
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(10^(1/2) + 10^(1/2)/2^(1/2))^2 = 29 Aug 2019, 08:20
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Is the answer B?

(2√10/√2)^2
4*10/2
40/2
20

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EncounterGMAT
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(10^(1/2) + 10^(1/2)/2^(1/2))^2 = 29 Aug 2019, 08:23
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IMO answer is option B

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(10^(1/2) + 10^(1/2)/2^(1/2))^2 = 29 Aug 2019, 11:22
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SajjadAhmad
\([\frac{\sqrt{10} + \sqrt{10}}{\sqrt{2}}]^2\)

A. 10
B. 20
C. 50
D. 100
E. 200
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\([\frac{\sqrt{10} + \sqrt{10}}{\sqrt{2}}]^2\)

= \([\frac{2\sqrt{10}}{\sqrt{2}}]^2\)

= \(\frac{4*10}{2}\)

= \(20\) , Answer must be (B)
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(10^(1/2) + 10^(1/2)/2^(1/2))^2 = 02 Sep 2019, 19:39
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SajjadAhmad
\([\frac{\sqrt{10} + \sqrt{10}}{\sqrt{2}}]^2\)

A. 10
B. 20
C. 50
D. 100
E. 200
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Simplifying, we have:

[(2√10)/√2]^2 = (2√5)^2 = 4 * 5 = 20

Answer: B
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