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26 Aug 2006, 07:32
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N
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please try this question...
explain ur answer
explain ur answer
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26 Aug 2006, 09:37
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(1) As each term after a1 is divisible by 5 and 4, it is divisible by 20. Thus there are an infinite number of terms that are divisible by 20. SUFF
(2) No information is given about terms after a6- NOT SUFF
(2) No information is given about terms after a6- NOT SUFF
26 Aug 2006, 09:47
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shinewine
Consider (1):
Rewrite given statement as:
a(n) = (4*5) 5^(n-2)
= 20*5^(n-2)
for all n>2,this will have 20 as a factor. - SUFF
Consider (2)
a(5)/a(4) = 4 and a(6)/a(5) = 5
We cannot get a common ration here without more data. - INSUFF
Answer: A
