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rookie06
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It must be A.

Since each employee of Z is an emploee of X or Y(but not both)
obviously the ration of Z must be in between that of X and Y

In statement 1 Ratio of y <z is given\
So ratio of x>z
i.e ratio ofy<z<x
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Let fx, fy, fz, px, py,pz be the numbers of full and part-time workers in each division

Is A= fx/px > fy>py=B?

(1) fy/py< (fy+fx)/(py+px)

pyfy +pxfy< fypy+fxpy
pxfy<fxpy

fy/py<fx/px SUFF

(2) More than half the full-time employees of Z are employees of X, while more than half the part-time time employees of Z are employees of Y.

fx>0.5fz so fy<0.5fz
py>0.5pz so px< 0.5pz

A>pz and B<pz SUFF

Answer: D
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Thanks everyone for attempting this. OA is D

kevincan - YOU ROCK!! You made the problem look so simple :)
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Hey kevin i neglected the second statement..........

Fine D



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