Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Sep 2107:00 PM EDT
-10:00 PM EDT
Boost your GMAT score in less than one month in a live online class + 6 months access to TTP OnDemand video courses included!
31 Jul 2020, 02:51
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
69% (02:39) correct
31%
(02:38)
wrong
based on 90
sessions
History
Date
Time
Result
Not Attempted Yet
[GMAT math practice question]
The figure shows that lines \(l\) and \(m\) are parallel to each other. What is the measure of \(∠x\)?
7.31ps.png [ 19.7 KiB | Viewed 3328 times ]
A. \(95^o\)
B. \(100^o\)
C. \(112^o\)
D. \(117^o\)
E. \(122^o\)
The figure shows that lines \(l\) and \(m\) are parallel to each other. What is the measure of \(∠x\)?
Attachment:
7.31ps.png [ 19.7 KiB | Viewed 3328 times ]
A. \(95^o\)
B. \(100^o\)
C. \(112^o\)
D. \(117^o\)
E. \(122^o\)
yashikaaggarwal
Senior Moderator - Masters Forum
Joined: 19 Jan 2020
Last visit: 10 Aug 2026
Posts: 3,094
Given Kudos: 1,510
Location: India
Schools: Cranfield (A) Warwick MiM "23 (M)
GPA: 4
WE:Analyst (Internet and New Media)
31 Jul 2020, 03:18
Kudos
Bookmarks
In triangle DEF,
Angle DFE + Angle DEF = 105° (exterior angle)
Also, angle DFE = 180-168 (supplement angle) and (opposite angles) = 12°
So.
Angle DFE + Angle DEF = 105°
12 + Angle DEF = 105
Angle DEF = 93°
Also Line AE is a transversal on parallel lines l and m
Angle DEF = Angle CAL = 93
Angle CAB = 180-93 = 87
In triangle ABC
Angle CAB + Angle CBA (opposite angle to 35°) = Angle X (exterior angle)
87 + 35 = X
X = 122.
Answer is E
Posted from my mobile device
Angle DFE + Angle DEF = 105° (exterior angle)
Also, angle DFE = 180-168 (supplement angle) and (opposite angles) = 12°
So.
Angle DFE + Angle DEF = 105°
12 + Angle DEF = 105
Angle DEF = 93°
Also Line AE is a transversal on parallel lines l and m
Angle DEF = Angle CAL = 93
Angle CAB = 180-93 = 87
In triangle ABC
Angle CAB + Angle CBA (opposite angle to 35°) = Angle X (exterior angle)
87 + 35 = X
X = 122.
Answer is E
Posted from my mobile device
Attachments
IMG_20200731_154147.jpg [ 40.88 KiB | Viewed 3181 times ]
31 Jul 2020, 10:12
Kudos
Bookmarks
MathRevolution
We can create a hexagon by closing the parallel lines. The sum of inner angles in a hexagon is 360 + 180 + 180, we can remove 180 from the two angles we created then subtract the rest of the angles. 540 - 145 - 105 - 168 = 540 - 418 = 122.
Ans: E
Attachments
hexagon.png [ 29.61 KiB | Viewed 3107 times ]
