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24 Dec 2020, 10:00
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Difficulty:
25%
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Question Stats:
82% (01:51) correct
18%
(02:06)
wrong
based on 61
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If the area of the rectangle in the figure below is equal to the area of the triangle, what is the perimeter of the triangle?
(A) 17
(B) \(8 + \sqrt{15}\)
(C) \(8 \sqrt{12}\)
(D) 40
(E) 42
2020-12-21_19-03-10.png [ 8.05 KiB | Viewed 1622 times ]
(A) 17
(B) \(8 + \sqrt{15}\)
(C) \(8 \sqrt{12}\)
(D) 40
(E) 42
Attachment:
2020-12-21_19-03-10.png [ 8.05 KiB | Viewed 1622 times ]
24 Dec 2020, 18:54
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Area of the rectangle = 10 * 6 = 60
Area of the triangle = (1/2) * 8 * height = 60 (Same as the rectangle)
Therefore height = 15
We use Pythagoras's theorem to find the hypotenuse = \(\sqrt{15^2 + 8^2} = \sqrt{289} = 17\)
The perimeter of the triangle = base + height + hypotenuse = 8 + 15 + 17 = 40
Option D
Arun Kumar
Area of the triangle = (1/2) * 8 * height = 60 (Same as the rectangle)
Therefore height = 15
We use Pythagoras's theorem to find the hypotenuse = \(\sqrt{15^2 + 8^2} = \sqrt{289} = 17\)
The perimeter of the triangle = base + height + hypotenuse = 8 + 15 + 17 = 40
Option D
Arun Kumar
24 Dec 2020, 23:41
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Given, 10*6 = 1/2 * 8 *height
So, height= 15.
Now, hypotenuse= Sqrt (15^2 + 8^2) = 17
Perimeter= 8+15 +17 = 40. Ans. D.
So, height= 15.
Now, hypotenuse= Sqrt (15^2 + 8^2) = 17
Perimeter= 8+15 +17 = 40. Ans. D.
