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17 Apr 2021, 14:29
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
65% (02:09) correct
35%
(02:26)
wrong
based on 26
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The right circular cone pictured below is cut horizontally at the midpoint of its height. If the smaller piece has a height of 3 and a volume of 9*pi, what is the volume of the larger piece?
A. 12*pi
B. 21*pi
C. 63*pi
D. 216*pi
E. 284*pi
A. 12*pi
B. 21*pi
C. 63*pi
D. 216*pi
E. 284*pi
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17 Apr 2021, 15:09
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Cone volume = (area base * height)/3 = (pi * radius^2)/3, so the botton cone has a base of radius 3.
The upper circle has double radius than the botton one. So the total cone has an area of 72pi (36pi * 6/3).
Substracting both cones: 72pi - 9pi = 63pi.
Answer C
The upper circle has double radius than the botton one. So the total cone has an area of 72pi (36pi * 6/3).
Substracting both cones: 72pi - 9pi = 63pi.
Answer C
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