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gk3.14
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ncp
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B

Consider the following case:
1)r...s...t...0
2)r...s...0...t
3)r...0....s...t
4)0...r...s....t

With II), only case 1) is possible
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I will go with C

r______s___t___0______-s
-4_____-2__-1___0______2

distance between t and –s = distance between t and r = 3

_r___0___s___t
-1___0___1__2
Here r and –s coincides
distance between t and –s = distance between t and r = 3



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