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07 Sep 2021, 03:56
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
49% (03:08) correct
51%
(03:04)
wrong
based on 35
sessions
History
Date
Time
Result
Not Attempted Yet
Attachment:
HN Armsterdam.jpg [ 5.78 KiB | Viewed 2478 times ]
A. \(216\) \(cm^2\)
B. \(324\) \(cm^2\)
C. \(208\) \(cm^2\)
D. \(276\) \(cm^2\)
E. \(278\) \(cm^2\)
07 Sep 2021, 12:49
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In the picture we see that triangle AKN is similar to triangle CMN.
CN=3*NA -> BM=MC=3*AK
area CMN = \(3^2\) * area AKN (realtion between sides is 3, so relation between areas is \(3^2\))
We also see that triangle BEM is similar to triangle AEK.
area BEM = \(3^2\) * area AEK
We also know that:
area AEN = area AKN + area AEK = 27
area ABC = area CMN + area BEM - area AEN = 9*area AKN + 9*area AEK - area AEN = 9*(area AKN + area AEK) - area AEN = 9*area AEN - area AEN = 8*area AEN = 8*27 = 216
IMO A
CN=3*NA -> BM=MC=3*AK
area CMN = \(3^2\) * area AKN (realtion between sides is 3, so relation between areas is \(3^2\))
We also see that triangle BEM is similar to triangle AEK.
area BEM = \(3^2\) * area AEK
We also know that:
area AEN = area AKN + area AEK = 27
area ABC = area CMN + area BEM - area AEN = 9*area AKN + 9*area AEK - area AEN = 9*(area AKN + area AEK) - area AEN = 9*area AEN - area AEN = 8*area AEN = 8*27 = 216
IMO A
Attachments
gmatclub_22.png [ 31.87 KiB | Viewed 2308 times ]
07 Sep 2021, 13:36
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andreagonzalez2k
No where is given ME perpendicular to BC , so how do u assume AKN is similar to CMN (so u cant say AK is perpendicular to EN) , only one angle is same , we are not sure of other two .
Seems some additional info is needed in question.
