by: Darkknight4463
14 mins
Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Sep 2601:00 PM EDT
-04:00 PM EDT
Top scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included. Class starts Saturdays Sept. 26, 2026 - Dec. 19, 2026, 1:00pm-4:00pm ES
Sep 2911:00 AM EDT
-01:00 PM EDT
" Description: Top scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included! Class starts Tues/Thur Sept. 29, 2026 - Dec. 3, 2026, 11:00am-1:00pm EST
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
39% (02:40) correct
61%
(03:09)
wrong
based on 74
sessions
History
Date
Time
Result
Not Attempted Yet
If the height of each box is \(\frac{2.8^2}{\sqrt{349}}\) meters, then how many more boxes could be placed on top of the pile?
(A) 0
(B) 1
(C) 2
(D) 6
(E) 7
Are You Up For the Challenge: 700 Level Questions
Attachment:
1.png [ 3.62 KiB | Viewed 3039 times ]
_________________
New to the GMAT Club?
- • Questions: Question Bank | Bunuel's Signature Collection
• Tests: GMAT Club Tests | Forum Quiz
• Guides: Quantitative | Critical Reasoning | Reading Comprehension | Ultimate Quant Guide | All You Need for Quant
• Rules: Quantitative | Verbal
Posts: 1,070
Bunuel
We can just ballpark.
20^2 = 400
19^2 = 361
\(\sqrt{349}\) is roughly 18.5
2.8^2 = 7.84
\(\frac{3\sqrt{349}}{7.84}\)
\(\frac{3(18.5)}{7.84}\)
55.5/7.84 = 7.1
We already have 6 boxes, so we have room for one more.
Answer choice B.
ThatDudeKnowsBallparking
Kinshook
Major Poster
Joined: 03 Jun 2019
Last visit: 17 Sep 2026
Posts: 6,132
Location: India
Schools: HBS '28 CBS '26 Wharton '26
GMAT 1: 690 Q50 V34
WE:Engineering (Transportation)
Products:
Asked: If the height of each box is \(\frac{2.8^2}{\sqrt{349}}\) meters, then how many more boxes could be placed on top of the pile?
Number of total boxes that could placed in the pile = \(\frac{3*\sqrt{349}}{2.8ˆ2} = 7.15 = 7\) since boxes are integers
Since 6 boxes are already in the pile, 1 more box can be placed on top of the pile.
IMO B
Moderator:
Announcements
Monday, Sep 14, 2026
11:30am NY / 3:30pm London / 9pm Mumbai
Subscribe to GMAT Club for New Podcast Episodes, Debriefs, & Insightful Sessions on GMAT Preparation
Tuck at Dartmouth
AI at Dartmouth Tuck: How the School Is Preparing Leaders for the Age of Artificial Intelligence
Inside the courses, research, and hands-on learning defining wise, decisive leadership in an AI-driven world.
Read More
Inside the courses, research, and hands-on learning defining wise, decisive leadership in an AI-driven world.
Read More
Top 5 GMAT Debrief Videos
Success stories and strategies from high-scoring candidates.