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21 Jun 2022, 16:15
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
80% (02:15) correct
20%
(02:54)
wrong
based on 10
sessions
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Date
Time
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Not Attempted Yet
In the given figure, ABCD is a rectangle with an area of 400 sq. units. What is the area (in sq. units) of the shaded region, if EB = 2/5*AB and BG = 1/4*BC ?
A 90
B 130
C 140
D 150
E 180
Attachment:
2021-03-09_22-23-20.png [ 12.74 KiB | Viewed 1962 times ]
21 Jun 2022, 17:01
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Theory involved:
Area of a triangle and proportions.
This questions takes time to be solved, but it’s a beautiful question.
Area of a triangle and proportions.
This questions takes time to be solved, but it’s a beautiful question.
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34EF9F4E-4A6C-462D-A4C2-CACF733F105E.jpeg [ 335.5 KiB | Viewed 1229 times ]
21 Jun 2022, 21:10
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Bunuel
The area of ABD is 200 since it is half the rectangle. Compare EBD to ABD. The heights are the same and the base of EBD is 40% the base of ABD. That means the area of EBD is 40% the area of ABD. Area of EBD is 40% of 200, which is 80.
The area of BCD is 200 since it is half the rectangle. Compare BGD to BCD (imagine BC and BG as the bases and CD as the height). The heights are the same and the base of BGD is 25% the base of BCD. That means the area of BGD is 25% the area of BCD. Area of BGD is 25% of 200, which is 50.
Area EBD+BGD = 80+50 = 130.
Answer choice B.
