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If the second set is contained in the 1st, it´ll always be possible that both have the same mean, median, range. What will never happen is that the second set, a subset of the 1st one, has a greater range. Thus, E.

Also, if you are going to scan or post images directly from the tests, please reduce/resize them, it´s a bit unconfortable to read from those extra-bulky images. Thanx
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I just used a smaller sample so it's easier to handle.

S contains 1, 2, 3, 4, 5
T could be any of the four numbers in S.

Mean of S = 3
Range of S = 5-1 = 4
Median of S = 3

We can pick any of the 4 numbers (without repeats) in Set T to test the statements.

A. If T contains 1, 2, 4, 5. Mean of T = 3
B. If T contains 1, 2, 4, 5. Median of T is 3
C. If T contains 1, 2, 4, 5. Range of T is 5-1=4
D. If T contains 1, 2, 3, 4. Mean of T = 2.5, which is less than Mean of S.
E. Range of S is 4. Here, no matter which 4 numbers you pick for T you can get a range that is greater than 4.

So E is the answer.



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