Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
May 2110:00 AM EDT
-11:59 PM EDT
Make the most of your break with the most realistic GMAT™ prep. Take up to $700 off select products.
May 2208:30 AM PDT
-09:30 AM PDT
For many Indian MBA applicants, the default dream has long been a top US MBA. But as career goals, visa considerations, timelines, and global mobility priorities evolve, more candidates are seriously considering MBA programs in Europe.- Jun 10
06:00 AM PDT
-06:15 PM PDT
Register for the GMAT Club Virtual MBA Spotlight Fair – the world’s premier event for serious MBA candidates. This is your chance to hear directly from Admissions Directors at nearly every Top 30 MBA program..
04 May 2007, 13:44
Kudos
Bookmarks
Can anyone explain this ?
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
04 May 2007, 14:24
Kudos
Bookmarks
The answer is B and this is how I got it:
We know that the median length is 140. This means that there are at least 2 pieces that are less than or equal to 140 and 2 pieces that are greater than or equal to 140.
using the avg equation of x+x/n=avg we know that the sum of all the pieces is 620.
Now, to make things easy on us, let's assume that the two shorter pieces are both 110 (I'm starting at C because it's in the middle). If we put those into the equation we get: 110+110+140+x+x=620, which simplifies to 2x=260
We know that these last two lengths (x) have to be greater than or equal to 140. So if we assume that they are equal to each other they have to be 130 each. This is less than the median, so answer C is not correct and you know you have to go lower.
If you try 100 you get 100+100+140+x+x=620 which simplifies to 340+2x=620 --> 2x=280 --> x=140. This satisifies the median requirement so the answer is B.
We know that the median length is 140. This means that there are at least 2 pieces that are less than or equal to 140 and 2 pieces that are greater than or equal to 140.
using the avg equation of x+x/n=avg we know that the sum of all the pieces is 620.
Now, to make things easy on us, let's assume that the two shorter pieces are both 110 (I'm starting at C because it's in the middle). If we put those into the equation we get: 110+110+140+x+x=620, which simplifies to 2x=260
We know that these last two lengths (x) have to be greater than or equal to 140. So if we assume that they are equal to each other they have to be 130 each. This is less than the median, so answer C is not correct and you know you have to go lower.
If you try 100 you get 100+100+140+x+x=620 which simplifies to 340+2x=620 --> 2x=280 --> x=140. This satisifies the median requirement so the answer is B.
04 May 2007, 16:04
Kudos
Bookmarks
that's how is did it
we know that mean of 5 numbers is 124 therefore sum of all number is 620
median is the middle number of sequence N1, N2, 140, N4, N5
we have to take the minimum possible number that is >=140 N4 and N5 and it is 140
so we have N1,N2, 140,140,140
We are interested in finding N1.
620-3*140=200
because all numbers are sorted the maximum number we can take is 200/2 =100
answer is 100
we know that mean of 5 numbers is 124 therefore sum of all number is 620
median is the middle number of sequence N1, N2, 140, N4, N5
we have to take the minimum possible number that is >=140 N4 and N5 and it is 140
so we have N1,N2, 140,140,140
We are interested in finding N1.
620-3*140=200
because all numbers are sorted the maximum number we can take is 200/2 =100
answer is 100
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
