Bunuel
City A and City B are located 610 kilometers (km) apart from each other on Highway X. At 8:00 a.m., Alonzo began driving along Highway X from City A to City B at an average driving speed of 90 kilometers per hour (km/h). At 9:30 a.m., on the same day, Ryan began driving along Highway X from City B to City A at an average driving speed of 100 km/h. How long, in hours and minutes to the nearest minute, did Ryan drive before meeting Alonzo on Highway X ?
A. 2 hours 30 minutes
B. 2 hours 50 minutes
C. 3 hours 13 minutes
D. 3 hours 55 minutes
E. 4 hours 0 minutes
Between 8:30 am and 9:00 am: Distance covered by Alonzo between 8:00 am and 9:30 am = 1.5 * 90 = 90 + 45 = 135 kms
At 9:30 am: Distance between Alonzo and Ryan = 610 - 135 = 475 kms
The ratio of distance covered when they meet will be in the ratio of their speed
Speed of Ryan / Speed of Alonzo = \(\frac{100}{90} = \frac{10}{9}\)
Therefore Ryan covers 10 out of 19 parts, and Alonzo covers the remaining 9.
Value of each of the 19 parts =\( \frac{475 }{ 19} = 25\)
Distance covered by Ryan = \(10 * 25\)
Speed of Ryan = \(100\)
Time taken = \(\frac{250}{100} = 2.5\) hours
Option A
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