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Difficulty:
35%
(medium)
Question Stats:
79% (02:21) correct
21%
(02:56)
wrong
based on 2056
sessions
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The Quasi JX is a new car model. Under ideal driving conditions, the Quasi Jx’s fuel economy is E kilometers per liter (E \(\frac{km}{L}\)) when its driving speed is constant at S kilometers per hour (S \(\frac{km}{h}\)).
In terms of the variables S and E, select the expression that represents the number of liters of fuel used in 1 hour of driving under ideal driving conditions at a constant speed S, and select the expression that represents the number of liters of fuel used in a 60 km drive under ideal driving conditions at a constant speed S. Make only two selections, one in each column.
In terms of the variables S and E, select the expression that represents the number of liters of fuel used in 1 hour of driving under ideal driving conditions at a constant speed S, and select the expression that represents the number of liters of fuel used in a 60 km drive under ideal driving conditions at a constant speed S. Make only two selections, one in each column.
| Liters of fuel in 1 hour | Liters of fuel in 60 km | |
| S/E | ||
| E/S | ||
| 60/E | ||
| 60/S | ||
| S/60 | ||
| E/60 |
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Posts: 10
fuel efficiency or mileage is basically: distance traveled / no. of liters. (km/L)
Hence, No. of liters = Distance traveled / fuel efficiency (mileage)
Liters of fuel consumed in 1 hour = speed * 1 / mileage = S / E
Liters of fuel consumed in 60 km = Distance / mileage = 60 / E
Hence, No. of liters = Distance traveled / fuel efficiency (mileage)
Liters of fuel consumed in 1 hour = speed * 1 / mileage = S / E
Liters of fuel consumed in 60 km = Distance / mileage = 60 / E
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Video solution here (3:15):
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General Discussion
S/E - represents litres of fuel in 1 hour
E is the economy in km for per litre, so for 1 km it would 1/E litre, so for 60 km - 60/E litres
Posted from my mobile device
E is the economy in km for per litre, so for 1 km it would 1/E litre, so for 60 km - 60/E litres
Posted from my mobile device
Posts: 16,401
Official Explanation
Strategize: Choose from the available options the expression that yields the intended value.
RO1, Liters of fuel in 1 hr: Strategize
The Quasi JX travels E kilometers per liter of fuel \((E\frac{km}{L})\) at S kilometers per hour \((S\frac{km}{hr})\). Therefore the Quasi JX requires \(\frac{1}{E}\) liters of fuel to travel 1 km. Since the Quasi JX travels S kilometers per hour, it requires \(\frac{1}{E}\) \(\frac{L}{km}\) × S \(\frac{km}{hr}\), or \(\frac{S}{E} \frac{L}{hr}\)
The correct answer is A, \(\frac{S}{E}\).
RO2, Liters of fuel in 60 km: Strategize
The Quasi JX travels E kilometers per liter of fuel \((E\frac{km}{L})\). Therefore the Quasi JX requires \(\frac{1}{E}\) liters of fuel to travel 1 km. Given this, the Quasi JX uses 1/E L/km × 60 km, or 60/E L of fuel to travel 60 km.
The correct answer is C, \(\frac{60}{E}\)
Strategize: Choose from the available options the expression that yields the intended value.
RO1, Liters of fuel in 1 hr: Strategize
The Quasi JX travels E kilometers per liter of fuel \((E\frac{km}{L})\) at S kilometers per hour \((S\frac{km}{hr})\). Therefore the Quasi JX requires \(\frac{1}{E}\) liters of fuel to travel 1 km. Since the Quasi JX travels S kilometers per hour, it requires \(\frac{1}{E}\) \(\frac{L}{km}\) × S \(\frac{km}{hr}\), or \(\frac{S}{E} \frac{L}{hr}\)
The correct answer is A, \(\frac{S}{E}\).
RO2, Liters of fuel in 60 km: Strategize
The Quasi JX travels E kilometers per liter of fuel \((E\frac{km}{L})\). Therefore the Quasi JX requires \(\frac{1}{E}\) liters of fuel to travel 1 km. Given this, the Quasi JX uses 1/E L/km × 60 km, or 60/E L of fuel to travel 60 km.
The correct answer is C, \(\frac{60}{E}\)
Posts: 67
Is therexa more reasonable way to solve this.
the most helpful reply is the simplest way of explaining it and the easiest way to solve it.
kayarat600
Posts: 478
Whenever you're confused about whether to multiply or divide, don't ask "Do I multiply or divide?" Instead, ask "What unit do I want, and what unit do I have?" The units will force the operation. If you have km/liter and want liters, divide by km/liter: Fuel = Distance ÷ (km per liter). For example, if a car gives 20 km/liter, then traveling 100 km uses 100 ÷ 20 = 5 liters, not 2000 liters. Similarly, if speed is 80 km/h and mileage is 20 km/liter, then in 1 hour the car travels 80 km and uses 80 ÷ 20 = 4 liters, so Fuel in 1 hour = Speed ÷ Mileage = S/E.
A useful rule is: to get the numerator unit, multiply; to get the denominator unit, divide. Also do a quick reality check—if your calculation gives an absurdly large or small number, you've probably used the wrong operation.
A useful rule is: to get the numerator unit, multiply; to get the denominator unit, divide. Also do a quick reality check—if your calculation gives an absurdly large or small number, you've probably used the wrong operation.
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