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23 Jan 2025, 11:45
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
(N/A)
Question Stats:
50% (00:57) correct
50% (01:56) wrong based on 4 sessions
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In the figure below, ABCD is a square and AED is an equilateral triangle. If AB = 2, what is the area of the shaded region?
\(A. \sqrt{3}\)
\(B. 2\)
\(C. 3\)
\(D. 4 – 2\sqrt{3} \)
\(E. 4 – \sqrt{3}\)
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25 Jan 2025, 11:37
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OE
Subtract to find the shaded area. The area of the square is 4. The area of the equilateral triangle (see Section 12-J) is \(\frac{2^2 \sqrt{3}}{4} = \frac{4\sqrt{3}}{4}=\sqrt{3}\) = . So the area of the shaded region is \(4 – \sqrt{3}.\)
Answer: E
Subtract to find the shaded area. The area of the square is 4. The area of the equilateral triangle (see Section 12-J) is \(\frac{2^2 \sqrt{3}}{4} = \frac{4\sqrt{3}}{4}=\sqrt{3}\) = . So the area of the shaded region is \(4 – \sqrt{3}.\)
Answer: E
