In a high-stakes racing competition, each car's performance is evaluat

Question

In a high-stakes racing competition, each car's performance is evaluated based on a combination of straight-line speed (x-axis) and turn speed (y-axis). The effectiveness of a car on certain racetracks can be ranked using a formula like 5x + 2y, where a higher result indicates better overall performance. The diagram below shows the stats for each car:

Based on the information in the diagram, answer the following questions:

The car with the highest overall performance score using the formula 2x + y is .

The car with the lowest overall performance score using the same formula is .

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Official Answer

Dropdown 1: Car 2 Dropdown 2: Car 7

Aarushi100 · Answer

In this problem, 
The car's overall performance is dependent on straight-line speed (x-axis) and turn speed (y-axis). The combination of the two is calculated using a formula 5x+2y.

For dropdown 1: 
The formula which is used the calculate the score is given:  2x+y 
For highest overall performance score, both x and y must be positive to yield a maximum value of 2x+y. 
From the graph we can see that car 2 has the value of x=4 and y=0, which yields 2(4)+0=8. 
Similarly, for Car 4 x=2, y=3 which yields 2(2)+3=7. 
We can check for all cars, in the positive quadrant but by eyeballing we already know that Car 2 and Car 4 are the only possible contenders and by calculation we have narrowed it down to Car 2.

For dropdown 2:
Again we have to use the same formula:  2x+y . 
Here, we adopt the opposite approach. 
For lowest overall performance score, both x and y must be negative to yield a minimum value of 2x+y.
From the graph we can see that Car 7 x= -5 , y=-1, yields the minimum value of 2(-5) +(-1) =-11.

Answer: 
First Dropdown: Car 2
Second Dropdown: Car 7

GmatTest2026 · Answer

Solution:

Given in the question stem:

1. The X-axis represents the straight-line speed.

2. The Y-axis represents the turn speed.

3. A car's effectiveness can be ranked using the formula 5x + 2y. (This formula represents the overall performance that is evaluated based on a combination of straight-line speed (x-axis) and turn speed (y-axis).)

1. The car with the highest overall performance score using the formula 2x + y is  Car 2 .

Car 1 = 2(1) + 5 = 7.

Car 2 = 2(4) + 0 = 8 + 0 = 8.

Car 4 = 2(2) + 3 = 4 + 3 = 7.

Car 6 = 2(3) + (-4) = 6 - 4 = 2.

Car 7 = 2(-5) + (-1) = -10 -1 = -11.

2. The car with the lowest overall performance score using the same formula is  Car 7 .

We have already calculated the car's performance above based on that. And, also by using the same formula, the lowest performance for Car 3 is 2(-1) + (-3) = -5, and Car 8 = 2(-2) + 0 = -4.

Bismuth83 · Answer

1. The question asks us to  evaluate the fastest and slowest cars, given the formula of effectiveness .

2. Since we are working with the formula 2x + y, it would be easier to convert the graph into a chart of all the x and y values:

Cars 
 x 
 y 
 2x + y 
 
  1 
 1 
 5

2 
 4 
 0

3 
 -1 
 -3

4 
 2 
 3

5 
 1 
 2

6 
 3 
 -4

7 
 -5 
 -1

8 
 -2 
 0

3. Now let's calculate what 2x + y would be for each of the cars.

Cars 
 x 
 y 
 2x + y 
 
  1 
 1 
 5 
 7 
 
  2 
 4 
 0 
 8 
 
  3 
 -1 
 -3 
 -5 
 
  4 
 2 
 3 
 7 
 
  5 
 1 
 2 
 4 
 
  6 
 3 
 -4 
 2 
 
  7 
 -5 
 -1 
 -11 
 
  8 
 -2 
 0 
 -4

4. The cars with the best overall performance is car 2 (8) and car 7 (-11), respectively.

5. Our answer will be:   D1 - Car 2 and D2 - Car 7  .

kshaurya · Answer

A simpler way to solve this problem is to vizualize the graph of 2x+y = 0.

Now for the 1st statement we know that both x&y positive will yield maximum value, therefore just compare the perpendicular distance of the points from the line 2x+y = 0, which will clearly be Car2. Hence that is the maximum value

For 2nd statement, we understand that both x&y negative will yield minimum value, So our point must be found in 3rd quadrant. So similarly vizualize 2x+y=0 and the farthest point in the 3rd quadrant is Car7

Logic: The more the perpendicular distance of a point from the line, the higher the intercept of a parallel line of the same slope, hence if 2x+y=0 has highest distance from Car2, the intercept of that line will be x=4. Therefore the line parallel to 2x+y = 0 will pass through that point & will have a value of 2*4+0 = 8

In a high-stakes racing competition, each car's performance is evaluat

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In a high-stakes racing competition, each car's performance is evaluat

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