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04 Jun 2025, 10:56
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
(N/A)
Question Stats:
50% (01:35) correct
50% (03:19) wrong based on 2 sessions
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You have a team of 5 people and 3 tasks to assign. Task A needs two people, Task B needs two people, and Task C needs one person. You are only going to assign one task to each person. In how many different ways can you assign the tasks?
14 Jun 2025, 02:27
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OE
Set up 5 slots, because you have five tasks to assign. Label two of the slots A, two other slots B, and the last slot C. You have 5 choices for the first slot, 4 for the second, on down to 1 choice for the last slot:
There are two sets of 2 repeated labels each, so divide by 2! twice to account for these two sets of repeats.
There are \(\frac{5*4*3*2*1}{2!2!=}=30\) possible task assignments.
Answer: 30
GMAT-Club-Forum-afgwqgi8.png [ 10.23 KiB | Viewed 252 times ]
Set up 5 slots, because you have five tasks to assign. Label two of the slots A, two other slots B, and the last slot C. You have 5 choices for the first slot, 4 for the second, on down to 1 choice for the last slot:
There are two sets of 2 repeated labels each, so divide by 2! twice to account for these two sets of repeats.
There are \(\frac{5*4*3*2*1}{2!2!=}=30\) possible task assignments.
Answer: 30
Attachment:
GMAT-Club-Forum-afgwqgi8.png [ 10.23 KiB | Viewed 252 times ]
