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07 Oct 2025, 05:34
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
62% (02:45) correct
38%
(02:28)
wrong
based on 137
sessions
History
Date
Time
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Not Attempted Yet
A function f(x) is defined for all the real values of z such that 3f(x) + 2f(1 - x) = x^2 - 3 What is the value of f(6)?
A) 8
B) 9
C) 10
D) 11
E) 12
Screenshot 2025-10-07 5.17.43 PM.png [ 106.65 KiB | Viewed 924 times ]
A) 8
B) 9
C) 10
D) 11
E) 12
Attachment:
Screenshot 2025-10-07 5.17.43 PM.png [ 106.65 KiB | Viewed 924 times ]
07 Oct 2025, 06:42
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Put x = 6
3f(6) + 2f(-5) = 33
Now put x = -5
3f(-5) + 2f(6) = 22
Let f(6) = a & f(-5) = b
3a + 2b = 33....Eq(1)
3b + 2a = 22....Eq(2)
We have 2 equations and 2 variables that can be easily solved using elimination
Eq(1)*3 and Eq(2)*2, we get
9a + 6b = 99
6b + 4a = 44
Eq(1) - Eq(2)
a = f(6) = 11
Hence, D
3f(6) + 2f(-5) = 33
Now put x = -5
3f(-5) + 2f(6) = 22
Let f(6) = a & f(-5) = b
3a + 2b = 33....Eq(1)
3b + 2a = 22....Eq(2)
We have 2 equations and 2 variables that can be easily solved using elimination
Eq(1)*3 and Eq(2)*2, we get
9a + 6b = 99
6b + 4a = 44
Eq(1) - Eq(2)
a = f(6) = 11
Hence, D
07 Oct 2025, 19:59
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Is there any other way to solve the above question?
paragw
