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17 Sep 2007, 01:07
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N
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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17 Sep 2007, 02:25
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St1:
r+s = 7 --> many combinations of r and s. insufficient.
St2:
(r+s)(r-s) = 7
7 is prime so has to be 7 and 1. So r,s must be 4 and 3. Sufficient.
Ans B
r+s = 7 --> many combinations of r and s. insufficient.
St2:
(r+s)(r-s) = 7
7 is prime so has to be 7 and 1. So r,s must be 4 and 3. Sufficient.
Ans B
17 Sep 2007, 02:31
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ywilfred
OA is C
