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27 Apr 2009, 19:28
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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100% (01:09) correct
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27 Apr 2009, 22:15
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From the combination u can notice that All the diigits will occur equal no of times in the Units, tens, hundreds positon.
To find how many times they occur equally = No of combinations/ No of digits = 24 / 4 = 6
For the units position alone : 6 ( 1 +2+3+ 4 ) = 60
Thousand + Hundreds + Tens + units = 60 *1000 + 60 * 100 + 60 *10 + 60 = 66660
To find how many times they occur equally = No of combinations/ No of digits = 24 / 4 = 6
For the units position alone : 6 ( 1 +2+3+ 4 ) = 60
Thousand + Hundreds + Tens + units = 60 *1000 + 60 * 100 + 60 *10 + 60 = 66660
27 Apr 2009, 22:47
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Excellent tkarthi! Thanks!
I managed to find the answer but by finding the last 3 digits, that is 660. Then picked E. Here's how:
If first two spots are 12 ---combinations for last two 34 + 43 = 77. Multiply by 2 because the combination when 21 one are the first two digits will be the same. Therefore, 77*2= 154
If first two spots are 13 ---combinations for last two 24 + 42 = 66. 66*2 = 132
If first two spots are 14 ---combinations for last two 32 + 23 = 55. 55*2 = 110
If first two spots are 23 ---combinations for last two 14 + 41 = 55. 55*2 = 110
If first two spots are 24 ---combinations for last two 13 + 31 = 44. 44*2 = 88
If first two spots are 34 ---combinations for last two 12 + 21 = 33. 33*2 = 66
154+132+110+110+88+66 = 660
Thus E.
I acknowledge that tkarthi's way is more comprehensive.
I managed to find the answer but by finding the last 3 digits, that is 660. Then picked E. Here's how:
If first two spots are 12 ---combinations for last two 34 + 43 = 77. Multiply by 2 because the combination when 21 one are the first two digits will be the same. Therefore, 77*2= 154
If first two spots are 13 ---combinations for last two 24 + 42 = 66. 66*2 = 132
If first two spots are 14 ---combinations for last two 32 + 23 = 55. 55*2 = 110
If first two spots are 23 ---combinations for last two 14 + 41 = 55. 55*2 = 110
If first two spots are 24 ---combinations for last two 13 + 31 = 44. 44*2 = 88
If first two spots are 34 ---combinations for last two 12 + 21 = 33. 33*2 = 66
154+132+110+110+88+66 = 660
Thus E.
I acknowledge that tkarthi's way is more comprehensive.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
