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14 Aug 2009, 03:37
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N
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100% (03:06) correct
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I know this is easy but can't seem to see it....
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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14 Aug 2009, 04:33
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Disclosure: I was able to solve this one only because the answer I would have marked was already marked by you and was wronged by GMATPREP!!
SOL:
Statements 1 & 2 are true.
St3:
LHS = a + b - ab + c - ac - bc + abc
For RHS, the trick is to refrain from applying our age-old maths rule of 'brackets take precedence over everything else'.......we do not know for sure what's the precedence of this operator that the question has defined. Thus we need to stick to the definition given in the question and expand RHS as follows:
RHS = a + (b o c) - a(b o c)
= a + b + c - bc - ab - ac + abc
Thus we observe that LHS = RHS!
ANS: E
SOL:
Statements 1 & 2 are true.
St3:
LHS = a + b - ab + c - ac - bc + abc
For RHS, the trick is to refrain from applying our age-old maths rule of 'brackets take precedence over everything else'.......we do not know for sure what's the precedence of this operator that the question has defined. Thus we need to stick to the definition given in the question and expand RHS as follows:
RHS = a + (b o c) - a(b o c)
= a + b + c - bc - ab - ac + abc
Thus we observe that LHS = RHS!
ANS: E
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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