Gmatprep (circle, coordinate geometry)

Question

I couldn't find this post...could someone please explain how to arrive at the answer. Thanks!

smartmundu · Answer

Both OP and OQ represents the radius of the circle,

First calculate OP = sq rt ( 3+1 )
 OP = OQ = 2

Now find the angle PO makes with the x-axis,

so we can say tanQ = sq rt (3) = 60 degree

this makes angles that oq makes with x-axis as 30 degree

now it is simple cos 30 = s/2

this results s = 1

simple circle & trigonometry concept

jakolik · Answer

Hi,

Let the angles (clockwise) at center O be u v x and y.
We have
v+x=90 
u+v+x+y=180
hence u+y=90

Drop a perpendicular from P to the x axis at point T.
triangle OPT is right triangle with sides 1,sqrt(3) and 3 and hence it is a 30-60-90 triangle.
Thus angle u is 30 degrees.
Thus angle y is 60 degrees.

Now, drop a perpendicular from Q to the x at point M
Triangle OQM is right triangle with angles 30,60,90 with ratio of sides 1 sqrt(3) and 2.
Hence OM is 1 and thus s =1

regards,
Jack

ghettosquad · Answer

Hope this helps:)

iPinnacle · Answer

Good tricky question

vittarr · Answer

Hope this will help

bumpbot · Answer

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Gmatprep (circle, coordinate geometry)

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