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arjtryarjtry
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PREP -- D2 11 Sep 2008, 21:37
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pls explain the meaning of this problem to me...



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PREP -- D2 11 Sep 2008, 21:55
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//A//
1: so m and p both are even and m is not a factor of p, r if p is divided by m will be at least 2. so suff..
2: if m = 5 and p = 6, r is 1. no.
if m = 10 and p = 15, r is 5. yes.
so nsf..
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PREP -- D2 13 Sep 2008, 01:35
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since both m and p are integers, should'nt r always be greater than or equal to 1..

for ex 5 divided by 4 or 8 divided by 3...

can someone please come up with a possibility where r is less than 1 except when there is perfect divisibility?
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PREP -- D2 13 Sep 2008, 09:06
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In addition to the question above,


so m and p both are even

Is this always true when the greatest common factor is 2? Is there a specific pattern for this?


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//A//
1: so m and p both are even and m is not a factor of p, r if p is divided by m will be at least 2. so suff..
2: if m = 5 and p = 6, r is 1. no.
if m = 10 and p = 15, r is 5. yes.
so nsf..
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PREP -- D2 14 Sep 2008, 01:39
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bigfernhead
In addition to the question above,


so m and p both are even

Is this always true when the greatest common factor is 2? Is there a specific pattern for this?


GMAT TIGER
//A//
1: so m and p both are even and m is not a factor of p, r if p is divided by m will be at least 2. so suff..
2: if m = 5 and p = 6, r is 1. no.
if m = 10 and p = 15, r is 5. yes.
so nsf..
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1)2*4 =p ,2*3=m in this case r=1
2)LCM=30=5*3*2 =>2,3,5,6,10,15,30 are the possible numbers INSUFFI

(1) and (2) SUFFI remainder!=1 henceANSWERS IMO C
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PREP -- D2 14 Sep 2008, 02:31
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arjtryarjtry
pls explain the meaning of this problem to me...
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1. 2 mx is even integer ==> r are even integer.
Thus mean r>1. ==> SUFF
2. Others mentioned. INSUFF.

A is correct answer.



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!