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singaks
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Can also be solved with binomial probability:

P(2 correct) + P (3 correct) = \(3C2*(1/2)^2*(1/2) + 3C3*(1/2)^3*(1/2)^0\)
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bmwhype2
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neelesh
Can also be solved with binomial probability:

P(2 correct) + P (3 correct) = \(3C2*(1/2)^2*(1/2) + 3C3*(1/2)^3*(1/2)^0\)
nice! thats how i set it up also.
+1
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singaks
A student has answered 7 of the 10 questions on the true-false test correctly and has decided to guess randomly on the rest. If all of the questions are equally weighted, what is the probability of the student receiving a score of 90% or more on the test?

90%: 1/2*1/2*1/2 *3

+90%: 1/2*1/2*1/2

3/8+1/8 =1/2



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