GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 19 Jun 2018, 20:49

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Probability

Author Message
Senior Manager
Joined: 04 Aug 2008
Posts: 363

### Show Tags

13 Oct 2008, 08:23
...

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.

Attachments

Clipboard02.jpg [ 26.02 KiB | Viewed 969 times ]

_________________

The one who flies is worthy. The one who is worthy flies. The one who doesn't fly isn't worthy

Intern
Joined: 30 Sep 2008
Posts: 10

### Show Tags

13 Oct 2008, 10:01
Hi,

I am going to take a shot at this. Hope I am correct and my methodology works. Please let me know.

(1) If more than 1/2 of the employees are women, then there could be 6, 7, 8, or 9 women. Using 6 women - 6/10 x 5/9 = 30/90. Therefore p < 1/2.
Using 9 women - 9/10 x 8/9 = 72/90. Therefore p > 1/2.

therefore statement 1 is not good.

(2) Since the probability for men will be 1/10 then probability of no women is 1/10. then probability of women (p) will be > 1/2.

My ans is B.
Intern
Joined: 01 Nov 2005
Posts: 44
Location: New jersey

### Show Tags

13 Oct 2008, 17:08
Hi,

I am also going to take a shot at this problem

(1)
as it is given that number of women is greaten than 1/2 therefore, number of women is eitehr 6 , 7 , 8 , 9

therefore,
6/10 * 7/10= .42

or
9/10 * 8/10 = .72

therefore, i agree statement 1 is not sufficient

2)

(2) Since the probability for men will be less then 1/10 then it is safe to assume that probably of women being selected is 9/10

_________________

Target +700
Life is like a box of chocolate, you never know what you gonna get..

Senior Manager
Joined: 26 Jan 2008
Posts: 260

### Show Tags

13 Oct 2008, 21:03
spiridon wrote:
...

(E)

(1) For 6 women, probability of both selections being women = (6/10) * (5/9) = 1/3
For 9 women, probability = (9/10) * (8/9) = 4/5
1/3 < 1/2 < 4/5 --- insufficient

(2) Probability of all men getting selected is below 1/10 when there are 3 or lesser men
With 3 men (and hence 7 women), p = 7/10 * 6/9 = 7/15
With 2 men (and hence 8 women), p = 8/10 * 7/9 = 28/45
7/15 < 1/2 < 28/45 --- insufficient

(1) and (2) do not provide any additional information. Insufficient.
_________________
Intern
Joined: 01 Nov 2005
Posts: 44
Location: New jersey

### Show Tags

05 Dec 2008, 04:27
i AM STRONGLY CONVINCED THAT ANSWER IS B. SOMEONE PLEASE GET THE OA

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.

_________________

Target +700
Life is like a box of chocolate, you never know what you gonna get..

Re: Probability   [#permalink] 05 Dec 2008, 04:27
Display posts from previous: Sort by

# Probability

Moderator: chetan2u

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.