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20 Mar 2009, 11:45
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Find the probability of a full house (three of a kind and two of another kind), say three kings and two aces.
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This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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20 Mar 2009, 14:18
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We can choose the two types of cards we'll have in 13*12 ways. We then need to choose three cards of the first type from the four cards available, and two cards of the second type from the four cards available. The probability is thus:
13*12*4C3*4C2/52C5
13*12*4C3*4C2/52C5
20 Mar 2009, 14:44
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IanStewart
thanks Ian, makes very much sense. I appreciate it.
Archived Topic
Hi there,
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