It is currently 19 Sep 2017, 06:50

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

probability : poker problem

  post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
Senior Manager
Senior Manager
avatar
Joined: 06 Jul 2007
Posts: 275

Kudos [?]: 53 [0], given: 0

probability : poker problem [#permalink]

Show Tags

New post 20 Mar 2009, 11:45
Find the probability of a full house (three of a kind and two of another kind), say three kings and two aces.



--== Message from GMAT Club Team ==--

This topic has been closed to new posts due to inactivity and/or due to the posting rules violation. It has been archived and locked. If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links:
Quantitative: https://gmatclub.com/forum/rules-for-po ... 33935.html
Verbal: https://gmatclub.com/forum/rules-to-pos ... 08733.html

We remove posts that do not follow our posting guidelines, and we reserve the right to remove any post for any reason. Thank you.

Kudos [?]: 53 [0], given: 0

Expert Post
GMAT Tutor
avatar
B
Joined: 24 Jun 2008
Posts: 1341

Kudos [?]: 1907 [0], given: 6

Re: probability : poker problem [#permalink]

Show Tags

New post 20 Mar 2009, 14:18
We can choose the two types of cards we'll have in 13*12 ways. We then need to choose three cards of the first type from the four cards available, and two cards of the second type from the four cards available. The probability is thus:

13*12*4C3*4C2/52C5
_________________

GMAT Tutor in Toronto

If you are looking for online GMAT math tutoring, or if you are interested in buying my advanced Quant books and problem sets, please contact me at ianstewartgmat at gmail.com

Kudos [?]: 1907 [0], given: 6

Senior Manager
Senior Manager
avatar
Joined: 06 Jul 2007
Posts: 275

Kudos [?]: 53 [0], given: 0

Re: probability : poker problem [#permalink]

Show Tags

New post 20 Mar 2009, 14:44
IanStewart wrote:
We can choose the two types of cards we'll have in 13*12 ways. We then need to choose three cards of the first type from the four cards available, and two cards of the second type from the four cards available. The probability is thus:

13*12*4C3*4C2/52C5


thanks Ian, makes very much sense. I appreciate it.

Kudos [?]: 53 [0], given: 0

Re: probability : poker problem   [#permalink] 20 Mar 2009, 14:44
Display posts from previous: Sort by

probability : poker problem

  post reply Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.