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# profit loss question explanation required!!!

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Intern
Joined: 23 Aug 2016
Posts: 2
profit loss question explanation required!!!  [#permalink]

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03 Oct 2016, 09:37
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By selling two articles for Rs X, Joey gains 30% on one and loses 30% on the other. What is the net profit/loss percentage suffered/gained by Joey?

A. loss of 15%
B. loss of 9%
C. no profit no loss
D. profit of 9%
E. profit of 15%

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Magoosh GMAT Instructor
Joined: 28 Dec 2011
Posts: 4493
Re: profit loss question explanation required!!!  [#permalink]

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03 Oct 2016, 11:56
2
By selling two articles for Rs X, Joey gains 30% on one and loses 30% on the other. What is the net profit/loss percentage suffered/gained by Joey?

A. loss of 15%
B. loss of 9%
C. no profit no loss
D. profit of 9%
E. profit of 15%

I'm happy to respond. My friend, understand that this question is not written with the clarity typical of GMAT question. In particular, it's not 100% clear whether the price stated, Rs X, is the value before the percents gain & loss, or whether it is the price received, after the gain & loss. If the former is the case, it's a very easy question. I believe the latter is the case, and that's a more challenging question. That's the version I'll solve here.

Let's assume that Joey sold these two items, each for the same price. For one item, the sale at that price represented a 30% gain over its value. For the other, the sale at that same price represented a 30% loss compared to its value. What is the total percent loss?

First, a conceptual approach. Let's say that the sale price for both items is Rs. 1000. The value of the first item is some P < 1000, and 1000 is a 30% increase on P. The value of the second item is some Q > 1000, and a 30% decrease in Q equals 1000. We gained 30% of P and lost 30% of Q. We know that Q > P, so 30% of Q is much larger than 30% of P. Therefore, the loss was greater than the gain, and there is net loss in the sale. Without any calculations, we see that either (A) or (B) has to be the answer. That's important to understand.

Now, let's think about calculating the exact numerical answer. Using those variables, we can create the equations
P*1.3 = X
Q*0.7 = X
Notice that 1.3 is the multiplier for a 30% increase and 0.7 is the multiplier for a 30% decrease.

Notice that to solve for P & Q, we will need to divide by 0.7 and 1.3. This means that a well-chosen value of X should be divisible by both 7 and 13. Let's just use 91 = 7*13.

We will say that X = 91. Joey sold each item for the same price, Rs 91.

The first item was worth P, and P*1.3 = 91. Thus, P = 91/1.3 = 70. The first item was worth Rs. 70 and sold for Rs 91, a 30% increase.

The second item was worth Q, and Q*0.7 = X. Thus, Q = 91/0.7 = 130. The second item was worth Rs. 130 and sold for Rs 91, a 30% loss.

The net value before the sales was P + Q = 200. The net gain from the two sales was 91 + 91 = 182. This is a percent loss

Percent loss = (200 - 182)/200 x 100% = 18/200 x 100% = 9/100 x 100% = 9%

The total loss is 9%.

Does all this make sense?
Mike
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Mike McGarry
Magoosh Test Prep

Education is not the filling of a pail, but the lighting of a fire. — William Butler Yeats (1865 – 1939)

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Re: profit loss question explanation required!!!  [#permalink]

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07 Oct 2016, 12:54
By selling two articles for Rs X, Joey gains 30% on one and loses 30% on the other. What is the net profit/loss percentage suffered/gained by Joey?

A. loss of 15%
B. loss of 9%
C. no profit no loss
D. profit of 9%
E. profit of 15%

Let selling price be Rs 910 each

Quote:
Joey gains 30% on one

So, Cost price = 910/130*100 => 700

Quote:
loses 30% on the other

So, Cost price = 910/70*100 => 1300

Total Cost is 1300 + 700 = 2000
Total Selling Price is 910*2 = 1820

As Cost Price > Selling Price , there is a loss...

% Loss = $$\frac{( 2000 - 1820 )}{2000} * 100$$

% Loss = $$\frac{180}{2000} * 100$$

% Loss = 9%

Hence answer will be B. loss of 9%.....
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Thanks and Regards

Abhishek....

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Re: profit loss question explanation required!!!  [#permalink]

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14 Nov 2017, 16:30
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Re: profit loss question explanation required!!! &nbs [#permalink] 14 Nov 2017, 16:30
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