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Hi, Need to need to approach to solve this kind of problem...
P varies as the product of Q & R. If P is trebled and Q is halved, what is change in R?
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P varies as the product of Q & R : This statement can be re-written as P=kQR where k is a constant
If P is trebled and Q is halved, what is change in R \(P_1=kQ_1R_1\) \(P_2=3P_1; Q_2=0.5Q_1\) \(P_2=kQ_2R_2\) \(3P_1=0.5kQ_1R_2\) Dividing, \(0.5R_2/R_1 = 3\) \(R_2=6R_1\)
Hi, Need to need to approach to solve this kind of problem...
P varies as the product of Q & R. If P is trebled and Q is halved, what is change in R?
Show more
When we say that P varies directly with Q, we mean that when P increases, Q increases proportionally. When P decreases, Q decreases proportionally. The word proportionally means that if P doubles, Q also doubles. If P becomes 1/3, Q also becomes 1/3 Mathematically, we write this as P α Q or P = kQ
e.g. The cost of renting a hall varies directly with the time for which it is rented. This means Cost = k*Time where k is a constant or Cost/Time = k, a constant. If you rent the hall for 1 hr, you pay $100. How much will you pay if you rent it for 4 hrs? If C = 100, T = 1, then k = 100/1 = 100 Now, if T = 4, what is C? C = kT, therefore, C = 100*4 = $400
There is also inverse variation. P varies inversely with Q means when P increases, Q decreasea proportionally and vice versa. Mathematically, P α 1/Q or PQ = k.
e.g. The cost of a standard gold coin is inversely proportional to the amount of impurities in it. So Cost * Impurities = k. If a standard gold coin has 4 gm impurities, its cost is $400. What is the amount of impurities in a $ 1200 coin. So, 4 * 400 = k = x * 1200 x = 4/3 gm
This is how you deal with variation. Your questions states P varies as product of Q and R. (directly is implied here) P = k*Q*R
\(\frac{P}{QR} = k = \frac{3P}{(Q/2)R'}\) P and Q get canceled and you get R' = 6R So R increases by 5R.
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