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# PS 30 students

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Senior Manager
Joined: 19 Mar 2008
Posts: 350

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24 Aug 2008, 06:47
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Intern
Joined: 10 Aug 2008
Posts: 22
Schools: Emory Goizueta (Class of 2013)
WE 1: Management consultant
WE 2: Marketing consultant

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24 Aug 2008, 08:21
D

30 students borrow a total of 60 books
the first 24 students borrowed 2*0+12*1+10*2=32 books
So the rest 6 students borrowed 28 books.
thus, the greatest book one student can borrow is 28-5*3=13
Director
Joined: 12 Jul 2008
Posts: 513
Schools: Wharton

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24 Aug 2008, 08:54
judokan wrote:

D

Total books borrowed = 30*2 = 60
# of known students = 2 + 12 +10 = 24
# of known books = 2*0 + 12*1 + 10*2 = 32

# of remaining students = 30 - 24 = 6
# of remaining books = 60 - 32 = 28

Remaining students borrowed at least 3 books each. To maximize single student borrowing, you must minimize the other 5 students' borrowing.
Max books for a single remaining student = 28 - 5*3 = 13
Re: PS 30 students   [#permalink] 24 Aug 2008, 08:54
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