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# ps - cube

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Intern
Joined: 07 Sep 2008
Posts: 25

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10 Oct 2008, 13:44
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if cube X has an edge of length e and cube Y has an edge of length e+1, how much greater is the total surface area of cube Y than that of cube X?

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Manager
Joined: 27 Sep 2008
Posts: 76

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10 Oct 2008, 15:12
cube surface area e

$$6e^2$$

cube surface area e+1

$$6(e+1)^2$$

$$6(e^2+2e+1)$$

$$6e^2+12e+6$$

solve:

$$(6e^2+12e+6)-(6e^2) = 12e+6$$

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

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Re: ps - cube   [#permalink] 10 Oct 2008, 15:12
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