Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 24 May 2017, 21:13

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# PS- GMAT Prep

 post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
Intern
Joined: 21 Apr 2006
Posts: 18
Location: San Francisco, CA
Followers: 0

Kudos [?]: 0 [0], given: 0

PS- GMAT Prep [#permalink]

### Show Tags

21 Jun 2006, 22:34
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Ok, I am stumped. How does one solve this question? Any clear & concise explanation will be appreciated.

2 Days till GMAT,
Tru
Attachments

math_01.gif [ 14.24 KiB | Viewed 761 times ]

VP
Joined: 25 Nov 2004
Posts: 1486
Followers: 7

Kudos [?]: 104 [0], given: 0

Re: PS- GMAT Prep [#permalink]

### Show Tags

22 Jun 2006, 01:00
t1 = 23
t2 = t1-3 = 23-3 = 20
t3 = t2 - 3 = t1 - 3 - 3 = t1 - 2 (3) = 23 - 2 (3) = 17
t4 = t3 - 3 = t2 - 3 - 3 - 3 = t1 - 3 (3) = 23 - 3 (3) = 14

we can establish a relationship as under:

tn = t1 - (n-1) (3)
-4 = t1- (n - 1) (3)
(n -1) (3) = 23 +4
(n-1) (3) = 27
n = 9 +1 = 10
VP
Joined: 15 Jun 2006
Posts: 1124
Schools: Chicago Booth
Followers: 5

Kudos [?]: 44 [0], given: 0

### Show Tags

22 Jun 2006, 04:09
Answer is 10
Every term of sequence is previous term minus three, sequence is
23-20-17-14-11-8-5-2-(-1)-(-4)
(-4) is the 10th term
Manager
Joined: 01 Jun 2006
Posts: 139
Followers: 1

Kudos [?]: 6 [0], given: 0

### Show Tags

22 Jun 2006, 04:12
We have t(n)=t(1)-(n-1)*3
So if t(n)=-4 => 23-3*(n-1)=4 => n=10
VP
Joined: 02 Jun 2006
Posts: 1261
Followers: 2

Kudos [?]: 87 [0], given: 0

### Show Tags

22 Jun 2006, 09:33
You can quickly go from t1 = 23 and list out the values
{23, 20, 17, 14, 11, 8,5,2,-1, -4} i.e. 10
Intern
Joined: 21 Apr 2006
Posts: 18
Location: San Francisco, CA
Followers: 0

Kudos [?]: 0 [0], given: 0

### Show Tags

22 Jun 2006, 10:03
It's all about the pattern! Thank you everyone.

-Tru
Director
Joined: 06 May 2006
Posts: 791
Followers: 3

Kudos [?]: 34 [0], given: 2

### Show Tags

22 Jun 2006, 16:02
tn = t1 + (n-1)d; question specifies d = -3

=> -4 = 23 - 3n + 3 => n = 30.
_________________

Uh uh. I know what you're thinking. "Is the answer A, B, C, D or E?" Well to tell you the truth in all this excitement I kinda lost track myself. But you've gotta ask yourself one question: "Do I feel lucky?" Well, do ya, punk?

Director
Joined: 07 Jun 2006
Posts: 513
Followers: 11

Kudos [?]: 130 [0], given: 0

### Show Tags

22 Jun 2006, 18:15
brcinsf wrote:
It's all about the pattern! Thank you everyone.

-Tru

Use nth term of a sequence = first_term+(n -1)(difference_in_terms)
(or usually remembered as Tn = a+(n-1)d

so -4 = 23 + (n-1)(-3) = 23 -3n +3

-4 = 26 -3n => n =10
22 Jun 2006, 18:15
Display posts from previous: Sort by

# PS- GMAT Prep

 post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.