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21 Jun 2006, 22:34
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N
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Ok, I am stumped. How does one solve this question? Any clear & concise explanation will be appreciated.
2 Days till GMAT,
Tru
2 Days till GMAT,
Tru
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Hi there,
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22 Jun 2006, 01:00
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t1 = 23
t2 = t1-3 = 23-3 = 20
t3 = t2 - 3 = t1 - 3 - 3 = t1 - 2 (3) = 23 - 2 (3) = 17
t4 = t3 - 3 = t2 - 3 - 3 - 3 = t1 - 3 (3) = 23 - 3 (3) = 14
we can establish a relationship as under:
tn = t1 - (n-1) (3)
-4 = t1- (n - 1) (3)
(n -1) (3) = 23 +4
(n-1) (3) = 27
n = 9 +1 = 10
t2 = t1-3 = 23-3 = 20
t3 = t2 - 3 = t1 - 3 - 3 = t1 - 2 (3) = 23 - 2 (3) = 17
t4 = t3 - 3 = t2 - 3 - 3 - 3 = t1 - 3 (3) = 23 - 3 (3) = 14
we can establish a relationship as under:
tn = t1 - (n-1) (3)
-4 = t1- (n - 1) (3)
(n -1) (3) = 23 +4
(n-1) (3) = 27
n = 9 +1 = 10
22 Jun 2006, 04:09
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Answer is 10
Every term of sequence is previous term minus three, sequence is
23-20-17-14-11-8-5-2-(-1)-(-4)
(-4) is the 10th term
Every term of sequence is previous term minus three, sequence is
23-20-17-14-11-8-5-2-(-1)-(-4)
(-4) is the 10th term
