Sure,

R=Ryegrass, B=Bluegrass, F=Fescue

X: 40% R, 60% B

Y: 25% R, 75% F

Mixture(lets call it M): 30% R, some B, some F

Question: What% of M is X

Since M is mixture, and ryegrass is M is from both X and Y,

Hence, the 30% of Ryegrass, will be the sum of ryegrass which comes from X and from Y.

Assume that the % of ryegrass contributed by X is x.

Total ryegrass = 30%

% from X= x%

Therefore, percentage from Y= (30-x)%

Now, in X the ratio of R:B = 40:60

Hence, if R=x, B=(60/40)x=3x/2

Similarly, in Y the ratio of R:F = 25:75

Hence, if R=30-x, F=(75/25)(30-x) = 3(30-x)

Adding all gives you 100%, so,

x + 3x/2 + (30-x) + 3(30-x) =100

solve for x => 40/3

B= 3x/2 => 20

To find total % of X in M, you have to add amount of B and amount of R from X

= 20 + 40/3 = 33.33

Hence B

Hope that makes sense!

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