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afife76
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|B+6|–|B–5|=0

I think mod problems should be tackled taking into consideration the ranges in which the exp are valid

B+6 > 0 if B > -6

B- 5 > 0 if B > 5

so there are 3 regions for which we have to consider the expression
B> 5 and -6 > B > 5 andB < -6

for B > 5 and D < -6 the equation has no soln
for the 2nd range B + 6 -(-(B - 5)) = 0
= B + 6 + B -5 = 0
2B = -1
or B= -.5
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K_s_r
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ian7777
any algebraic equation with absolute value must be rewritten in its positive and negative form without the absolute value.

For example,
|x| = 6 so
x = 6 and x = -6

|x-3| = 5 becomes
x-3 = 5 and x-3 = -5 so
x=8 and x=-2, and both work when you plug them back in.

Same thing here.
Start with |b+6|-|b-5|=0, and make it
|b+6|=|b-5|

So b+6 = b-5 or b+6 = -(b-5)
Solve each one, and see that in the first one, b cancels and it's impossible, and in the second one, b=-.5


Taking time in to consideration, this will be the quickest method to solve the problem



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