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ajay_gmat
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ajay_gmat
The numbers 1,2,3,4,5,6 are to be arranged around a circle. How many ways can the numbers 5,6 together but the number 4 is not next to either 5 or 6 ??


can't be 270. The total number of ways of arranging these numbers, making sure that 5 and 6 are together is (5-1)!*2! = 48.

out of these we have to subtract cases in which 4 is on either side of 5 or 6. There are 3!*2! such cases. So, total number of favourable ways is

48 - 12 = 36.

By the way, you chose a wrong forum to discuss this question.



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