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PS: Percents

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PS: Percents [#permalink]

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New post 04 Nov 2008, 23:59
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I'm having a hard time with this question:

At a certain health club, 30 percent of the members use both the pool and sauna, but 40 percent of the members who use the pool do not use the sauna. What percent of the members of the health club use the pool?

Answer: 50%

Thanks!

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SVP
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Joined: 17 Jun 2008
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Re: PS: Percents [#permalink]

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New post 05 Nov 2008, 00:14
If P is the number of healthclub members using pool and x is total number of healthclub members, then
0.4P = P - 0.3x
or, 0.3x = 0.6P
or, P = 1/2x = 50%.

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Manager
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Joined: 23 Aug 2008
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Re: PS: Percents [#permalink]

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New post 05 Nov 2008, 08:51
oatmealcrisp wrote:
I'm having a hard time with this question:

At a certain health club, 30 percent of the members use both the pool and sauna, but 40 percent of the members who use the pool do not use the sauna. What percent of the members of the health club use the pool?

Answer: 50%

Thanks!

My explanation:

1) from the question: "40 percent of the members who use the pool do not use the sauna", this means "60% of the members who use the pool DO use the sauna"

2) therefore, the "30 percent of the members use both the pool and sauna" represents only 60% of the pool users, as shown in statement (1)

3) so to get 100% of the pool users: take the 30% and divide by 60% = (0.3/0.6) = 50%

Kudos [?]: 54 [0], given: 0

Re: PS: Percents   [#permalink] 05 Nov 2008, 08:51
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