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# PS-Probability integer

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Senior Manager
Joined: 05 Jun 2008
Posts: 294

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02 Dec 2008, 08:26
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As a part of a game, four people each much secretly chose an integer between 1 and 4 inclusive. What is the approximate likelihood that all four people will chose different numbers?
Manager
Joined: 05 Nov 2008
Posts: 133
Location: NY, NY
Schools: Darden, Stern, CBS, Johnson, Fuqua

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02 Dec 2008, 09:23
vivektripathi wrote:
As a part of a game, four people each much secretly chose an integer between 1 and 4 inclusive. What is the approximate likelihood that all four people will chose different numbers?

1*(3/4)*(2/4)*(1/4) = 6/64 = 3/32

The first person can pick any number (probability of 1).
The second person can pick any of the 3 remaining numbers (probability of 3/4).
The third can pick any of the remaining 2 (probability of 2/4 or 1/2).
The last can pick 1 of the 4 numbers (probability of 1/4).

Multiply each of these together to get the total probability (likelihood) = 3/32
Manager
Joined: 14 Oct 2008
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02 Dec 2008, 09:42
vivek, Can you pls also post the answer choices when you post the Question. That would help.

Thanks.
Re: PS-Probability integer   [#permalink] 02 Dec 2008, 09:42
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