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PS - Sequence addition

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Manager
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Joined: 12 Apr 2006
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PS - Sequence addition [#permalink]

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New post 24 Jun 2009, 04:03
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A
B
C
D
E

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Please explain the shortest possible method for this type of question. TIA

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Director
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Joined: 03 Jun 2009
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WE 1: 5.5 yrs in IT
Re: PS - Sequence addition [#permalink]

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New post 24 Jun 2009, 04:40
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On a quick look, one can say that the series would be something like:

1/2 - 1/4 + 1/8 - 1/16 +1/32 - 1/64 ...
=(1/2 - 1/4) + (1/8 - 1/16) +(1/32 - 1/64) ...
= 1/4 + 1/16 + 1/64 ....

Now, since all these are fractional values, less then 1, and values decreasing as we move on, certainly the sum would be a small value less then 1.

So, options A and B are out.

Option E is out, since the series is 1/4 + ...+ve values

Now, for C and D :
For the sum of the series to be > 1/2, we would need to add 1/4 (or higher value) to the 1st term (i.e. 1/4). But as all the subsequent terms are 1/4th of the previous term and the value keeps on decreasing as we move to the right, the sum would be something near 1/4 (and cannot be greater then 1/2).

Hence answer D.
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Kudos [?]: 883 [1], given: 56

Re: PS - Sequence addition   [#permalink] 24 Jun 2009, 04:40
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