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# PS-Sum of even integers.jpg

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Manager
Joined: 21 May 2008
Posts: 83

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10 Oct 2008, 06:47
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PS-Sum of even integers.jpg [ 9.11 KiB | Viewed 889 times ]

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

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Intern
Joined: 22 Aug 2008
Posts: 3
Re: PS-Sum of even integers  [#permalink]

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10 Oct 2008, 14:40
7550.
explanation-
2+4+6+...+100 = 2550.
sum of all even integers from 102 to 200 is
102+104+106+...+200
=(100+2)+(100+4)+(100+6)+....+(100+100)
=(2+4+6+....+100)+(50*100)
=2550+5000
Senior Manager
Joined: 21 Apr 2008
Posts: 265
Location: Motortown
Re: PS-Sum of even integers  [#permalink]

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10 Oct 2008, 14:48
7550

102 + 104 + 106 + .... 200
100 + 2 + 100 + 4 + 100 + 6 ..... 100+100
50*100 + (2+4+6 ...100)

= 5000 + 2550 = 7550
Current Student
Joined: 28 Dec 2004
Posts: 3280
Location: New York City
Schools: Wharton'11 HBS'12
Re: PS-Sum of even integers  [#permalink]

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10 Oct 2008, 14:54
first figure how how many integers there are between 102-200

200=102+(n-1)(2) => n=50

sum= 50/2 (2*102+49*2)=7550
Manager
Joined: 27 Sep 2008
Posts: 76
Re: PS-Sum of even integers  [#permalink]

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10 Oct 2008, 15:43
lets see an easy one

2+4+6+8+10 = 30

2(1+2+3+4+5) = 30

we know that 1+2+3+4+5 = 5*6/2 (the last one*last one+1)/2

so 2*(5*6/2) = 30

solve

2*(100*101)/2-2*(50*51)/2 = 7550

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
Re: PS-Sum of even integers &nbs [#permalink] 10 Oct 2008, 15:43
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