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11 Jun 2007, 10:12
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If two integers between –5 and 3, inclusive, are chosen at random, which of the following is most likely to be true?
(A) The sum of the two integers is even
(B) The sum of the two integers is odd
(C) The product of the two integers is even
(D) The product of the two integers is odd
(E) The product of the two integers is negative
(A) The sum of the two integers is even
(B) The sum of the two integers is odd
(C) The product of the two integers is even
(D) The product of the two integers is odd
(E) The product of the two integers is negative
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11 Jun 2007, 10:47
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Lets analyze this one by one.
Between -5 and 3 (inclusive) there are 6 odd numbers -5.-3,-1,1,3 and there are 4 evens -4,-2,2
There are 5 negative and 3 positive numbers
I am tempted to intuitively say that product of 2 integers being even seems to be the best bet, but lets check the probabilities in detail :
A) happens when both numbers are odd or both are even : 6/10*5/9 + 4/10*3/9 = 7/15
B) happens if one odd and one even 6/10*4/9+4/10*6/9=9/15
C)happens when one of the numbers is even = 1- P(both are odd)
= 1 - ( 6/10 * 5/9) = 1-1/3 - 2/3 = 10/15
D)happens when both numbers are odd = 6/10 * 5/9 =1/3 or 5/15
E) happens when one of the numbers is <0>=0) = 1 - (4/10*3/9) = 13/15 --> AHA moment
Ans E , Is this the OA ?
Between -5 and 3 (inclusive) there are 6 odd numbers -5.-3,-1,1,3 and there are 4 evens -4,-2,2
There are 5 negative and 3 positive numbers
I am tempted to intuitively say that product of 2 integers being even seems to be the best bet, but lets check the probabilities in detail :
A) happens when both numbers are odd or both are even : 6/10*5/9 + 4/10*3/9 = 7/15
B) happens if one odd and one even 6/10*4/9+4/10*6/9=9/15
C)happens when one of the numbers is even = 1- P(both are odd)
= 1 - ( 6/10 * 5/9) = 1-1/3 - 2/3 = 10/15
D)happens when both numbers are odd = 6/10 * 5/9 =1/3 or 5/15
E) happens when one of the numbers is <0>=0) = 1 - (4/10*3/9) = 13/15 --> AHA moment
Ans E , Is this the OA ?
11 Jun 2007, 11:29
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From a first glence, I'd pick C
Analyzing the problem:
Set: [-5, -4, -3, -2, -1, 0, 1, 2, 3] (total 9 integers)
# negatives: 5
# positives: 3
# Zeros: 1
# Evens: 4
# Odds: 5
Now, lets calculate the probablity or the likelyhood of each event:
(A) The sum of the two integers is even
That'll be when picking 2 odds or 2 evens
P(A)= 5/9 x 4/8 + 4/9 x 3/8 = 32/72 = 4/9
(B) The sum of the two integers is odd
That holds when picking 1 odd and 1 even
P(B) = 5/9 x 4/8 + 4/9 x 5/8 = 2 x 20/72 = 40/72 = 5/9
(C) The product of the two integers is even
That'll be true when picking eithe 1 even 1 odd or 2 evens.
P(C) = P(B) + 4/9 x 3/8 = 5/9 + 12/72 = 5/9 + 1/6 = 39/54
(D) The product of the two integers is odd
That holds when picking two odds only ..
P(D) = 5/9 x 4/8 = 20/72 = 5/18 = 2.5/9
(E) The product of the two integers is negative
that holds when picking one negative and one positive
P(E) = 5/9 x 3/8 + 3/9 x 5/8 = 30/72 = 5/12
Yahoooo. My first glence worked out perfectly and my stats courses in college are helping me now
..
39/54 has the largest value among all answer choices.
Answer: C
Analyzing the problem:
Set: [-5, -4, -3, -2, -1, 0, 1, 2, 3] (total 9 integers)
# negatives: 5
# positives: 3
# Zeros: 1
# Evens: 4
# Odds: 5
Now, lets calculate the probablity or the likelyhood of each event:
(A) The sum of the two integers is even
That'll be when picking 2 odds or 2 evens
P(A)= 5/9 x 4/8 + 4/9 x 3/8 = 32/72 = 4/9
(B) The sum of the two integers is odd
That holds when picking 1 odd and 1 even
P(B) = 5/9 x 4/8 + 4/9 x 5/8 = 2 x 20/72 = 40/72 = 5/9
(C) The product of the two integers is even
That'll be true when picking eithe 1 even 1 odd or 2 evens.
P(C) = P(B) + 4/9 x 3/8 = 5/9 + 12/72 = 5/9 + 1/6 = 39/54
(D) The product of the two integers is odd
That holds when picking two odds only ..
P(D) = 5/9 x 4/8 = 20/72 = 5/18 = 2.5/9
(E) The product of the two integers is negative
that holds when picking one negative and one positive
P(E) = 5/9 x 3/8 + 3/9 x 5/8 = 30/72 = 5/12
Yahoooo. My first glence worked out perfectly and my stats courses in college are helping me now
..
39/54 has the largest value among all answer choices.
Answer: C
. I hope I dont do this on test day which is a week away now.
