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19 Jul 2020, 05:03
Kudos
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In 2001 there were 6 members in Binod's family and their average age was 28 years. He got married between 2001 and 2004 and in 2004 there was an addition of a child in his family. In 2006, the average age of his family is 32 years.
What is the present age (in 2006) of Vinod wife (in years) is:
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What is the present age (in 2006) of Vinod wife (in years) is:
Posted from my mobile device
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19 Jul 2020, 05:35
Kudos
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Please post your question with options and also add the source of the question.
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Thanks.
Ignatius1307
19 Jul 2020, 05:43
Kudos
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In 2001 there were 6 members in Binod's family and their average age was 28 years
Using Sum = Average * Count
Sum of ages of 6 members = 28*6 = 168
He got married between 2001 and 2004 and in 2004 there was an addition of a child in his family
Age of child in 2004=0
In 2006, the average age of his family is 32 years.
Let Age of wife is x in 2006
Age of child in 2006 = 2006 - 2004 = 2 yrs
Sum of Ages of 6 members excluding wife and child in 2006 = Sum of their age in 2001 + (2006-2001)*6 [ As each one of them will increase in age so multiplying by 6]
Sum of Ages of 6 members excluding wife and child in 2006 = 168 + 5*6 = 168 + 30 = 198
Sum of Ages of all family members of Binod in 2006 = Sum of Ages of 6 members excluding wife and child in 2006 + Age of wife in 2006 + Age of child in 2006
= 198 + x + 2 = 200 + x
=> In 2006, the average age of his family = \(\frac{Sum}{Count}\) = \(\frac{200+x}{8}\) [ 6 members including Binod + Wife + child ]
=> In 2006, the average age of his family = \(\frac{200+x}{8}\) = 32 [Given]
=> 200 + x = 32*8
=> x = 256-200 = 56
So, answer will be 56 [His wife delivered at the age of 54]
Hope it helps!
Using Sum = Average * Count
Sum of ages of 6 members = 28*6 = 168
He got married between 2001 and 2004 and in 2004 there was an addition of a child in his family
Age of child in 2004=0
In 2006, the average age of his family is 32 years.
Let Age of wife is x in 2006
Age of child in 2006 = 2006 - 2004 = 2 yrs
Sum of Ages of 6 members excluding wife and child in 2006 = Sum of their age in 2001 + (2006-2001)*6 [ As each one of them will increase in age so multiplying by 6]
Sum of Ages of 6 members excluding wife and child in 2006 = 168 + 5*6 = 168 + 30 = 198
Sum of Ages of all family members of Binod in 2006 = Sum of Ages of 6 members excluding wife and child in 2006 + Age of wife in 2006 + Age of child in 2006
= 198 + x + 2 = 200 + x
=> In 2006, the average age of his family = \(\frac{Sum}{Count}\) = \(\frac{200+x}{8}\) [ 6 members including Binod + Wife + child ]
=> In 2006, the average age of his family = \(\frac{200+x}{8}\) = 32 [Given]
=> 200 + x = 32*8
=> x = 256-200 = 56
So, answer will be 56 [His wife delivered at the age of 54]
Hope it helps!
