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27 Jul 2009, 19:56
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The circumference of the front wheel of a cart is 30 ft long and that of the back wheel is 36 ft long. What is the distance traveled by the cart, when the front wheel has done five more revolutions than the rear wheel?
A. 20 ft
B. 25 ft
C. 750 ft
D. 900 ft
E. 1000 ft
A. 20 ft
B. 25 ft
C. 750 ft
D. 900 ft
E. 1000 ft
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27 Jul 2009, 21:41
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Let x be the revolutions made by the rear wheel
therefore 30(x+5) = 36x ==> 30x+150 - 36x
== > x = 25
therefore 36x = 36*25 = 900
Answer is D
therefore 30(x+5) = 36x ==> 30x+150 - 36x
== > x = 25
therefore 36x = 36*25 = 900
Answer is D
27 Jul 2009, 23:25
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AndersonBound
Its D,
Let X be no. of the revolutions made by rear wheel, then X+ 5 are the no. of revolutions made by front wheel.
So X x36 = (X+ 5)30
on solving we get X =25
Hence Distance travelled by cart = 36 x 25 = 900 ft
