May 24 10:00 PM PDT  11:00 PM PDT Join a FREE 1day workshop and learn how to ace the GMAT while keeping your fulltime job. Limited for the first 99 registrants. May 25 07:00 AM PDT  09:00 AM PDT Attend this webinar and master GMAT SC in 10 days by learning how meaning and logic can help you tackle 700+ level SC questions with ease. May 27 01:00 AM PDT  11:59 PM PDT All GMAT Club Tests are free and open on May 27th for Memorial Day! May 27 10:00 PM PDT  11:00 PM PDT Special savings are here for Magoosh GMAT Prep! Even better  save 20% on the plan of your choice, now through midnight on Tuesday, 5/27
Author 
Message 
TAGS:

Hide Tags

eGMAT Representative
Joined: 04 Jan 2015
Posts: 2852

Question of the Week 19 (A store sells equal number of Vanilla .....)
[#permalink]
Show Tags
Updated on: 19 Oct 2018, 06:34
Question Stats:
62% (02:35) correct 38% (02:22) wrong based on 148 sessions
HideShow timer Statistics
eGMAT Question of the Week #19A store sells equal number of Vanilla and Coco flavoured candies, each in one of the coloured wrappers: Red, Green, Blue, and Violet. The ratio of total number of Red, Green, Blue, and Violet candies is 2:3:4:1, in every flavour. Now, without seeing the colour of the wrapper, Harry randomly picked up one of the candies, hoping that it will be a Green Vanilla flavoured candy. What is the probability that the selected candy will have at least one of the two features, wished by Harry? A. \(\frac{1}{2}\)
B. \(\frac{11}{20}\)
C. \(\frac{13}{20}\)
D. \(\frac{4}{5}\)
E. \(\frac{17}{20}\)
Official Answer and Stats are available only to registered users. Register/ Login.
_________________



Manager
Joined: 14 Jun 2018
Posts: 223

Re: Question of the Week 19 (A store sells equal number of Vanilla .....)
[#permalink]
Show Tags
19 Oct 2018, 06:27
Ratio of color = 2:3:4:1. Total = 10x out of which 5x is vanilla and 5x is coco. Probability of green = 3/10 ; Not green = 7/10 Probability of vanilla = 1/2 ; coco = 1/2 Probability of at least one of the two features of Green Vanilla = 1 None of the feature = 1  7/10 * 1/2 = 13/20
Option C



Intern
Joined: 17 May 2018
Posts: 49

Re: Question of the Week 19 (A store sells equal number of Vanilla .....)
[#permalink]
Show Tags
19 Oct 2018, 09:34
You could also quickly write down a simple table to count the desired outcomes, then divide that by the total number of outcomes to obtain the probability. We see that we have 10 coco flavoured candy + 3 green vanilla candy, which makes 13 out of a total of 20 available candy. p = 13 / 20 Answer C
Attachments
table.png [ 3.1 KiB  Viewed 964 times ]
_________________
¿Tienes que presentar el GMAT y no sabes por dónde empezar? ¡Visita GMAT para Principiantes y recibe el curso completo gratis!



eGMAT Representative
Joined: 04 Jan 2015
Posts: 2852

Re: Question of the Week 19 (A store sells equal number of Vanilla .....)
[#permalink]
Show Tags
24 Oct 2018, 01:05
Solution Given:• A store sells equal number of Vanilla and Coco flavoured candies, each in one of the coloured wrappers: {Red, Green, Blue and Violet} • The ratio of total number of red, green, blue and violet candies is 2: 3: 4: 1, in every flavour • Wishing a green vanilla flavoured candy, Harry randomly picked up one candy To find:• The probability that the selected candy will be either Green coloured or Vanilla flavoured or both.
Approach and Working: • Let us assume the total number of candies = 20x • Then, the number of vanilla and coco flavoured candies will be = 10x and 10x. • And, the number of red, green, blue and violet candies, in each of the two flavours, are 2x, 3x, 4x and x respectively
• Now, from the above table, we can see that the number of candies which are either green coloured or vanilla flavoured = 2x + 3x + 4x + x + 3x = 13x • Therefore, the probability = \(\frac{13x}{20x} = \frac{13}{20}\)
Hence, the correct answer is option C. Answer: CNote: The logic behind assuming the total number of candies as 20x is that there are a total of 20 parts ((2+ 3 + 4 +1)*2) of candies of different flavours packed in different coloured wrappers.
_________________



Intern
Joined: 19 Nov 2018
Posts: 4
Location: United States
GPA: 2.36

Re: Question of the Week 19 (A store sells equal number of Vanilla .....)
[#permalink]
Show Tags
30 Nov 2018, 02:27
Much easier if you approach it as P(a) + P(b)  P(a&b) 50% +30%  15% = 65% Answer is C




Re: Question of the Week 19 (A store sells equal number of Vanilla .....)
[#permalink]
30 Nov 2018, 02:27






