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Charlie45
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jcgoodchild
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Charlie45
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ywilfred
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H = -16t^2 + 64t

It hits the ground when h becomes 0.

t(64-16t) = 0
t = 0 (invalid) or t = 64/16 = 16/4 = 4
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sm176811
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Yeah this is a simple Kinematics problem

typically, S=ut + 1/2 a(t^2) where S is the distance, u is the initial velocity, a is the acceleration and t is the time..

In this case S (or H) == 0.

Then you can simply work on the quaratic equation. the values of t should be 0 and some other root.

You will have 2 choose the non zero root.
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rao_raghunath
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Good one.. trick is you have to know the height will be zero when it hits ground.
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sm176811
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ywilfred said
Quote:
t = 0 (invalid)


Is NOT invalid. When the object has not left the hand (just when it is launched) t==0.
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Charlie45
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Based on my recent test experience and what I read from others, I feel like they are asking more trick questions like this on the GMAT. Questions in which the calculation might be fairly simple however its a matter of making the connection that the H=0. Some of you might say, well yeah its obvious that H is 0. But in reality, when you are in a test environment and under time pressure, these sort of things might not always come to you as intuitively as you would think. Unfortunately, there is also little preparation one can do for these kind of problems, in some ways they are more like a critical reasoning problem in nature than like the traditional problem solving questions that you see in the official guide.
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I totally agree! And the thing is none of the prep materials - Kaplan, PR, PP, OG have these kind of questions!



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