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R is a set containing 8 different numbers. S is a set containing 7
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25 Feb 2012, 04:06
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58% (01:24) correct 42% (01:38) wrong based on 304 sessions
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R is a set containing 8 different numbers. S is a set containing 7 different numbers, all of which are members of R. Which of the following statements CANNOT be true? (A) The range of R is less than the range of S. (B) The mean of R is greater than the mean of S. (C) The range of R is equal to the range of S. (D) The mean of R is less than the mean of S. (E) The mean of R is equal to the mean of S. I got he right answer ( ) but had to some guess work on choice D. Any idea how can we prove that choice can be true as well?
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Re: R is a set containing 8 different numbers. S is a set containing 7
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25 Feb 2012, 04:39
enigma123 wrote: R is a set containing 8 different numbers. S is a set containing 7 different numbers, all of which are members of R. Which of the following statements CANNOT be true?
(A) The range of R is less than the range of S. (B) The mean of R is greater than the mean of S. (C) The range of R is equal to the range of S. (D) The mean of R is less than the mean of S. (E) The mean of R is equal to the mean of S.
I got he right answer (A) but had to some guess work on choice D. Any idea how can we prove that choice D can be true as well? The range of a set is the difference between the largest and smallest elements of a set.So, the answer is straight A: the range of a subset cannot be more than the range of a whole set: how can the difference between the largest and smallest elements of a subset be more than the difference between the largest and smallest elements of a whole set. As for D: Consider set R to be {3, 2, 1, 0, 1, 2, 3, 4} > mean=0.5. (D) The mean of R is less than the mean of S > remove the smallest term 3, then the mean of S will be 1, so more than 0.5. Hope it's clear.
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Re: R is a set containing 8 different numbers. S is a set containing 7
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07 May 2014, 03:59
HI Bunuel, consider this Set R = { 1,2,3,4,5,6,7,8} and set S = {1,2,3,5,6,7,8}, in this case, the range for both set R and set S is 7.
Kindly let me know if am missing something here ?
Thanks



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Re: R is a set containing 8 different numbers. S is a set containing 7
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07 May 2014, 04:34
virinchiwiwo wrote: HI Bunuel, consider this Set R = { 1,2,3,4,5,6,7,8} and set S = {1,2,3,5,6,7,8}, in this case, the range for both set R and set S is 7.
Kindly let me know if am missing something here ?
Thanks Yes, the ranges are equal but what's your question?
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Re: R is a set containing 8 different numbers. S is a set containing 7
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11 Oct 2017, 22:30
construct a set R=1,2,3,4,5,6,7,8=range=81=7 and mean=4 If S=1, 2,3,4,5,6,7=range=71=6 and mean is=4 If S=2,3,4,5,6,7,8=range=82=6 and mean is=35/7=5 so A is not possible and E, D,C are possible.
as for B Let R=0,1,2,3,4,5,6,7,mean=28/8=3.8 Let X=0,1,2,3,4,5,6, mean=21/7=3 hence B is also possible.



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Re: R is a set containing 8 different numbers. S is a set containing 7
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16 Oct 2017, 15:53
enigma123 wrote: R is a set containing 8 different numbers. S is a set containing 7 different numbers, all of which are members of R. Which of the following statements CANNOT be true?
(A) The range of R is less than the range of S. (B) The mean of R is greater than the mean of S. (C) The range of R is equal to the range of S. (D) The mean of R is less than the mean of S. (E) The mean of R is equal to the mean of S. Since every number from set S is in set R, there is no way for the range of set S to be greater than that of set R. Thus, answer A cannot be true. Answer: A
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Re: R is a set containing 8 different numbers. S is a set containing 7 &nbs
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