Raj and Tonya each participated in an experiment

For Tonya: P1 = 140, V1 = 1, T1= 300, n1 = moles transferred from Tonya (we really don't need to know the unit of n1 and can be thought as units)


For Raj: P2 = 60, V2 = 2, T2= 280, n2 = moles received by Raj


Since \(\frac{PV}{nRT}\) is a constant, hence \(\frac{P_1 \space * \space V_1}{n_1 \space * \space T_1} = \frac{P_2 \space * \space V_2}{n_2 \space * \space T_2}\) (R is a constant, it cancels out and so do Options 1 and 2)


Substituting the values, we get, \(\frac{140 \space * \space 1}{n_1 \space * \space 300} = \frac{60 \space * \space 2}{n_2 \space * \space 280}\)


\(\frac{n_1}{n_2} = \frac{140 \space * \space 1 * \space 280}{60 \space * \space 2 * \space 300} = \frac{49}{45}\)


This indicates that when Tonya transferred 49 units, Raj received 45 units. So 49 - 45 = 4 units of the 49 transferred was lost = \(\frac{4}{49}\)



Option C

Arun Kumar

Question: What fraction of the argon was lost in the transfer from Tonya to Raj?

n1 is the amount Tonya had and n2 is the amount Raj had.

We get n1/n2 = 49/45 or n2/n1 = 45/49

This means that for every 49 parts that Tonya had, Raj got only 45 parts. So 4 parts were lost.
What fraction of the gas was lost? 4 parts out of 49 parts were lost. So 4/49 was lost.

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