Let's simplify!
We can't uniform the bases, but it's obvious that exponents can be simplified (they are all multiples of 6).

First,
\(2^{120} = (2^{20})^6\)
\(3^{72}=(3^{12})^6\)
\(17^{30}=(17^5)^6\)

ok, this didn't help much, but let's try to compare only 2 at a time:

\(2^{120} = (2^{20})^6 = (2^{5})^{24} = 32^{24}\)
\(3^{72}=(3^{12})^6 = (3^{3})^{24} = 27^{24}\)

Clearly, I > II

Great! Now, lets compare first and third (120 and 30 are easier).

\(2^{120} = (2^{4})^{30} = 16^{30}\), clearly < \(17^{30}\)

Hence, III > I > II. Answer:

Spoiler: ::

C

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