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axl169
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axl169
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axl169
The correct answer was A. 37.5. But I don't know understand how that is.

Yes the answer will be 37.5

Speed of train X = 100/5 mph
Speed of train y = 100/3 mph

Let's say when the 2 trains meet, X had travelled m miles. and Y had traveled 100-m miles.

Since the trains started at the same time, they would have taken same time to cover m and 100-m miles respectively.

m/(100/5) = 100-m/(100/3)
5m = 300-3m
8m = 300
m = 37.5 miles
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SimaQ
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Alternatively you can solve this this way:

Train X: rate=100/5=20miles/hour; time=t; d=d
Train Y: rate=100/3=33*1/3miles/hour; time=t; d=100-d

construct two equations: r*t=d.... train x: 20*t=d
train y: 33*1/3t=100-d

then solve...

33*1/3t=100-20t
33*1/3t+20t=100
53*1/3t=100
t=300/160
t=1.875

The questions asks how many miles had train x trveled... we know the formula: r*t=d

We go back to the begining and plug in the values for train x....
r=20 miles/hour; t=1.875;d=?

20*1.875=37.5
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Clearly the speeds ratio of A and B is 3:5
So distance covered by them when they meet each other also will be in the ration 3:5

So distance covered by A is 3/8 x 100 = 37.5

Hence A.

Keep it simple....... Get the concepts of ratios.............Save time in the exam

Regards,
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cicerone
Clearly the speeds ratio of A and B is 3:5
So distance covered by them when they meet each other also will be in the ration 3:5

So distance covered by A is 3/8 x 100 = 37.5

Hence A.

Keep it simple....... Get the concepts of ratios.............Save time in the exam

Regards,


Cicerone
Where do you get 3/8 from? I like your ratio method of doing this.
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cicerone
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$uckafr33
cicerone
Clearly the speeds ratio of A and B is 3:5
So distance covered by them when they meet each other also will be in the ration 3:5

So distance covered by A is 3/8 x 100 = 37.5

Hence A.

Keep it simple....... Get the concepts of ratios.............Save time in the exam

Regards,

Cicerone
Where do you get 3/8 from? I like your ratio method of doing this.


Hey look at the bold part
Since the distance is shared in the raio of 3:5
A should cover 3/8 and in the same time B will cover 5/8 .............
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SimaQ
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cicerone
Clearly the speeds ratio of A and B is 3:5
So distance covered by them when they meet each other also will be in the ration 3:5

So distance covered by A is 3/8 x 100 = 37.5

Hence A.

Keep it simple....... Get the concepts of ratios.............Save time in the exam

Regards,


Yes, it works in this example, but it is better to have a clear concept of solving such problems. This ratio example won't work for other "rate" problems...
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cicerone
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SimaQ
cicerone
Clearly the speeds ratio of A and B is 3:5
So distance covered by them when they meet each other also will be in the ration 3:5

So distance covered by A is 3/8 x 100 = 37.5

Hence A.

Keep it simple....... Get the concepts of ratios.............Save time in the exam

Regards,

Yes, it works in this example, but it is better to have a clear concept of solving such problems. This ratio example won't work for other "rate" problems...


Hey SimaQ, please do not say this..............
Any question form Time and Distance out of Speed , Distance and Time if one of them is constant, i bet i will do it using ratios only..............
Why don't u try to test me........
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cicerone's method is neater but this is how i did it. trick to remember with this type of question where 2 things travel towards each other is that together they travel the total distance, whether its lifts, trains, cars, water going down a pipe, frogs etc :roll: :roll:

so

where t = time

100/5 t + 100/3 t = 100
300/15 t + 500/15 t = 100
t = 1500/800 = 15/8

15/8 * 100/5 = 75/2 = 37.5
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Speed of X is 100/5 = 20.0 m/h.
Speed of Y is 100/3 = 33.3 m/h.

now if X and Y met, that means total distance travelled would be 100 miles (since both start from opposite ends).

adding up the speed gives the consolidated speed which is 20 + 33.3 = 53.3 miles/hour

now, again applying distance-time formula, time taken is 100/53.3 = approx 2 hours.

so, X and Y met after 2 hours of their journey.

X travelled less than 40 miles in approximately 2 hours..

hence A.
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a)37.5

The time after which both trains meet = t
At time t, total distance traveled = 100 miles.

distance traveled by x = (100/5)*t
distance traveled by y = (100/3)*t

Putting these together,

(100/5)*t + (100/3)*t = 100
Simplifying, we get t=15/8

In 15/8 hrs, train X has traveled: 20*(15/8) = 37.5



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